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Handbook Steel Wire Ropes Type Of Ropes, Rope

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<strong>Handbook</strong>/04-Berechnung/01/01-03T01.doc/Date: 14.08.2003/ Page 4 of 4<br />

Factors, Areas, Masses and Breaking Forces (3.10)<br />

Fillfactor = f<br />

f =<br />

A<br />

Nominal Metallic Cross-Sectional area Factor = C<br />

C =<br />

f<br />

Au<br />

π<br />

⋅<br />

4<br />

(3.10.1)<br />

(3.10.2)<br />

Nominal Metallic Cross-Sectional area = A A = C ⋅ d 2 (3.10.3)<br />

Calculated Metallic Cross-Sectional area = Ac<br />

Ac = ∑ n π 2<br />

(3.10.4)<br />

Measured Metallic Cross-Sectional area = Ac<br />

4<br />

π<br />

4<br />

1<br />

Am = ∑ n<br />

1<br />

δ<br />

δ<br />

2<br />

m<br />

(3.10.5)<br />

<strong>Rope</strong> Length Mass Factor = W (3.10.6)<br />

Nominal <strong>Rope</strong> Length Mass = M M = W ⋅ d 2 (3.10.7)<br />

Measured <strong>Rope</strong> Length Mass = Mm (3.10.8)<br />

Breaking Force Factor = K<br />

πf<br />

⋅ k<br />

K =<br />

(3.10.9)<br />

Minimum Breaking Force = Fmin<br />

Fmin =<br />

4<br />

2<br />

d ⋅ Rr<br />

⋅ K<br />

1000<br />

(3.10.10)<br />

<strong>Rope</strong> Grade Rr (3.10.11)<br />

Calculated Minimum Breaking Force = Fc.min (3.10.12)<br />

Measured Breaking Force = Fm (3.10.13)<br />

Minimum Aggregate Breaking Force = Fe.min<br />

Fe.min =<br />

2<br />

d ⋅ C ⋅ Rr<br />

1000<br />

(3.10.14)<br />

Calculated Minimum Aggregate Breaking Force = Fe.c.min (3.10.15)<br />

Reduced Minimum Aggregate Breaking Force = Fe.red.min (3.10.16)<br />

Measured Aggregate Breaking Force = Fe.m (3.10.17)<br />

Measured Reduced Aggregate Breaking Force = Fe.red.m (3.10.18)<br />

Calculated Measured Breaking Force = Fmc (3.10.19)<br />

Calculated Measured Aggregate Breaking Force = Fe.m.c (3.10.20)<br />

Measured Total Spinning Loss (3.10.21)<br />

Measured Partial Spinning Loss (3.10.22)<br />

Spinning Loss Factor = k (3.10.23)<br />

Measured Total Spinning Loss Factor = km (3.10.24)<br />

Measured Partial Spinning Loss Factor = kp.m (3.10.25)<br />

Outer <strong>Wire</strong> Factor = a<br />

Outer <strong>Wire</strong> Diameter = δa δa = a ⋅ d<br />

4

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