Handbook Steel Wire Ropes Type Of Ropes, Rope
Handbook Steel Wire Ropes Type Of Ropes, Rope
Handbook Steel Wire Ropes Type Of Ropes, Rope
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<strong>Handbook</strong>/04-Berechnung/01/01-03T01.doc/Date: 14.08.2003/ Page 4 of 4<br />
Factors, Areas, Masses and Breaking Forces (3.10)<br />
Fillfactor = f<br />
f =<br />
A<br />
Nominal Metallic Cross-Sectional area Factor = C<br />
C =<br />
f<br />
Au<br />
π<br />
⋅<br />
4<br />
(3.10.1)<br />
(3.10.2)<br />
Nominal Metallic Cross-Sectional area = A A = C ⋅ d 2 (3.10.3)<br />
Calculated Metallic Cross-Sectional area = Ac<br />
Ac = ∑ n π 2<br />
(3.10.4)<br />
Measured Metallic Cross-Sectional area = Ac<br />
4<br />
π<br />
4<br />
1<br />
Am = ∑ n<br />
1<br />
δ<br />
δ<br />
2<br />
m<br />
(3.10.5)<br />
<strong>Rope</strong> Length Mass Factor = W (3.10.6)<br />
Nominal <strong>Rope</strong> Length Mass = M M = W ⋅ d 2 (3.10.7)<br />
Measured <strong>Rope</strong> Length Mass = Mm (3.10.8)<br />
Breaking Force Factor = K<br />
πf<br />
⋅ k<br />
K =<br />
(3.10.9)<br />
Minimum Breaking Force = Fmin<br />
Fmin =<br />
4<br />
2<br />
d ⋅ Rr<br />
⋅ K<br />
1000<br />
(3.10.10)<br />
<strong>Rope</strong> Grade Rr (3.10.11)<br />
Calculated Minimum Breaking Force = Fc.min (3.10.12)<br />
Measured Breaking Force = Fm (3.10.13)<br />
Minimum Aggregate Breaking Force = Fe.min<br />
Fe.min =<br />
2<br />
d ⋅ C ⋅ Rr<br />
1000<br />
(3.10.14)<br />
Calculated Minimum Aggregate Breaking Force = Fe.c.min (3.10.15)<br />
Reduced Minimum Aggregate Breaking Force = Fe.red.min (3.10.16)<br />
Measured Aggregate Breaking Force = Fe.m (3.10.17)<br />
Measured Reduced Aggregate Breaking Force = Fe.red.m (3.10.18)<br />
Calculated Measured Breaking Force = Fmc (3.10.19)<br />
Calculated Measured Aggregate Breaking Force = Fe.m.c (3.10.20)<br />
Measured Total Spinning Loss (3.10.21)<br />
Measured Partial Spinning Loss (3.10.22)<br />
Spinning Loss Factor = k (3.10.23)<br />
Measured Total Spinning Loss Factor = km (3.10.24)<br />
Measured Partial Spinning Loss Factor = kp.m (3.10.25)<br />
Outer <strong>Wire</strong> Factor = a<br />
Outer <strong>Wire</strong> Diameter = δa δa = a ⋅ d<br />
4