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(no lateral bracing specified) = 3

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Introduction to Wood Design<br />

38 × 184 mm sloping rafters are untreated<br />

and belong to the Spruce-Pine-Fir group. They<br />

will be seasoned and the service conditions<br />

will be dry.<br />

Design the heel joint between the 38 × 184 mm<br />

and two 38 × 235 mm members using nails.<br />

heel Connection<br />

Try 3in (76 mm) long common round<br />

wire nails<br />

diameter = 3.66 mm<br />

Required penetration in the head side<br />

member is 3d F.<br />

3 × 3.66 = 11 mm < 38 mm<br />

Required penetration in the point side<br />

member is 5d F.<br />

5 × 3.66 = 18 mm < 38 mm<br />

Design for <strong>lateral</strong> strength resistance<br />

Factored tensile force, N f<br />

N f = 2500 N<br />

Factored resistance, N r<br />

where<br />

N r = ϕN un F n sJ F<br />

ϕ = 0.8<br />

N u = n u(K D K SF K T)<br />

n u = unit <strong>lateral</strong> strength resistance per<br />

nail or spike, N<br />

n F = number of fasteners in<br />

the connection<br />

n s = 1 (nails are in single shear)<br />

J F = J eJ AJ BJ D<br />

J e = 1.0 (nails are driven into side grain)<br />

J A = 1.0 (nails are <strong>no</strong>t toe nailed)<br />

J B = 1.0 (nails are <strong>no</strong>t clinched)<br />

J D = 1.0 (<strong>no</strong>t used in diaphragm<br />

construction)<br />

J F = 1.0 × 1.0 × 1.0 × 1.0<br />

= 1.0<br />

11-63<br />

unit Lateral Strength Resistance<br />

The penetration depth of the nail is 76 mm<br />

(3 inch), therefore this is a two member<br />

wood to wood connection.<br />

For two-member connections, only Items (a),<br />

(b) and (d) to (g) of the yield equations are<br />

considered valid.<br />

where<br />

t 1 = 38 mm<br />

d F = 3.66 mm<br />

f 2 = 50G(1 – 0.01d F)<br />

= 50 × 0.42 × (1 – 0.01 × 3.66)<br />

= 20 MPa<br />

G = 0.42 (CSA O86, Table A. 10.1)<br />

t 2 = 38 mm<br />

f 3 = 110G 1.8 (1 – 0.01d F)<br />

= 110 × 0.42 1.8 × (1 – 0.01 × 3.66)<br />

= 22 MPa<br />

f y = 50(16 – d F)<br />

= 50 × (16 – 3.66)<br />

= 617 MPa<br />

For lumber side plates:<br />

f 1 = 50G(1 – 0.01d F)<br />

= 20 MPa<br />

(a) f1dFt1 = 20 × 3.66 × 38<br />

= 2814 N<br />

(b) f2dFt2 = 20 × 3.66 × 38<br />

= 2714 N<br />

(d) f 2 c<br />

1dF 1<br />

6 (f<br />

f3<br />

fy<br />

+ f) f<br />

1 t1<br />

+ m<br />

5 d<br />

1 3<br />

= 20 × 3.66 2 ×<br />

1 22 617 1 38<br />

c # # + # m<br />

6 (20 + 22) 20 5 3.66<br />

= 996 N<br />

1<br />

F

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