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Basics of Fluid Mechanics - The Orange Grove

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8 CHAPTER 1. INTRODUCTION<br />

Combining equation (1.9) with equation (1.6) yields<br />

τxy = µ δβ<br />

δt<br />

(1.10)<br />

If the velocity pr<strong>of</strong>ile is linear between the plate (it will be shown later that it is<br />

consistent with derivations <strong>of</strong> velocity), then it can be written for small a angel that<br />

δβ<br />

δt<br />

= dU<br />

dy<br />

(1.11)<br />

Materials which obey equation (1.10) referred to as Newtonian fluid. For this kind<br />

<strong>of</strong> substance<br />

τxy = µ dU<br />

dy<br />

(1.12)<br />

Newtonian fluids are fluids which the ratio is constant. Many fluids fall into this<br />

category such as air, water etc. This approximation is appropriate for many other<br />

fluids but only within some ranges.<br />

Equation (1.9) can be interpreted as momentum in the x direction transfered<br />

into the y direction. Thus, the viscosity is the resistance to the flow (flux) or<br />

the movement. <strong>The</strong> property <strong>of</strong> viscosity, which is exhibited by all fluids, is due to<br />

the existence <strong>of</strong> cohesion and interaction between fluid molecules. <strong>The</strong>se cohesion<br />

and interactions hamper the flux in y–direction. Some referred to shear stress<br />

as viscous flux <strong>of</strong> x–momentum in the y–direction. <strong>The</strong> units <strong>of</strong> shear stress are<br />

the same as flux per time as following<br />

F<br />

A<br />

kg m<br />

sec 2<br />

1<br />

m2 <br />

= ˙m U<br />

A<br />

kg<br />

sec<br />

m<br />

sec<br />

1<br />

m2 <br />

Thus, the notation <strong>of</strong> τxy is easier to understand and visualize. In fact, this interpretation<br />

is more suitable to explain the molecular mechanism <strong>of</strong> the viscosity. <strong>The</strong><br />

units <strong>of</strong> absolute viscosity are [N sec/m 2 ].<br />

Example 1.1:<br />

A space <strong>of</strong> 1 [cm] width between two large plane surfaces is filled with glycerine.<br />

Calculate the force that is required to drag a very thin plate <strong>of</strong> 1 [m 2 ] at a speed <strong>of</strong><br />

0.5 m/sec. It can be assumed that the plates remains in equiledistance from each<br />

other and steady state is achived instanly.<br />

SOLUTION<br />

Assuming Newtonian flow, the following can be written (see equation (1.6))<br />

F =<br />

A µU<br />

h<br />

∼ 1 × 1.069 × 0.5<br />

0.01<br />

= 53.45[N]

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