Basics of Fluid Mechanics - The Orange Grove
Basics of Fluid Mechanics - The Orange Grove
Basics of Fluid Mechanics - The Orange Grove
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8 CHAPTER 1. INTRODUCTION<br />
Combining equation (1.9) with equation (1.6) yields<br />
τxy = µ δβ<br />
δt<br />
(1.10)<br />
If the velocity pr<strong>of</strong>ile is linear between the plate (it will be shown later that it is<br />
consistent with derivations <strong>of</strong> velocity), then it can be written for small a angel that<br />
δβ<br />
δt<br />
= dU<br />
dy<br />
(1.11)<br />
Materials which obey equation (1.10) referred to as Newtonian fluid. For this kind<br />
<strong>of</strong> substance<br />
τxy = µ dU<br />
dy<br />
(1.12)<br />
Newtonian fluids are fluids which the ratio is constant. Many fluids fall into this<br />
category such as air, water etc. This approximation is appropriate for many other<br />
fluids but only within some ranges.<br />
Equation (1.9) can be interpreted as momentum in the x direction transfered<br />
into the y direction. Thus, the viscosity is the resistance to the flow (flux) or<br />
the movement. <strong>The</strong> property <strong>of</strong> viscosity, which is exhibited by all fluids, is due to<br />
the existence <strong>of</strong> cohesion and interaction between fluid molecules. <strong>The</strong>se cohesion<br />
and interactions hamper the flux in y–direction. Some referred to shear stress<br />
as viscous flux <strong>of</strong> x–momentum in the y–direction. <strong>The</strong> units <strong>of</strong> shear stress are<br />
the same as flux per time as following<br />
F<br />
A<br />
kg m<br />
sec 2<br />
1<br />
m2 <br />
= ˙m U<br />
A<br />
kg<br />
sec<br />
m<br />
sec<br />
1<br />
m2 <br />
Thus, the notation <strong>of</strong> τxy is easier to understand and visualize. In fact, this interpretation<br />
is more suitable to explain the molecular mechanism <strong>of</strong> the viscosity. <strong>The</strong><br />
units <strong>of</strong> absolute viscosity are [N sec/m 2 ].<br />
Example 1.1:<br />
A space <strong>of</strong> 1 [cm] width between two large plane surfaces is filled with glycerine.<br />
Calculate the force that is required to drag a very thin plate <strong>of</strong> 1 [m 2 ] at a speed <strong>of</strong><br />
0.5 m/sec. It can be assumed that the plates remains in equiledistance from each<br />
other and steady state is achived instanly.<br />
SOLUTION<br />
Assuming Newtonian flow, the following can be written (see equation (1.6))<br />
F =<br />
A µU<br />
h<br />
∼ 1 × 1.069 × 0.5<br />
0.01<br />
= 53.45[N]