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18. Large cardinals

18. Large cardinals

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Lemma <strong>18.</strong>9. Let A be a set of infinite <strong>cardinals</strong> such that for every regular cardinal<br />

κ, the set A ∩ κ is non-stationary in κ. Then there is a one-one regressive function with<br />

domain A.<br />

Proof. We proceed by induction on γ def<br />

= ⋃ A. Note that γ is a cardinal; it is 0 if<br />

A = ∅. The cases γ = 0 and γ = ω are trivial, since then A = ∅ or A = {ω} respectively.<br />

Next, suppose that γ is a successor cardinal κ + . Then A = A ′ ∪ {κ + } for some set A ′<br />

of infinite <strong>cardinals</strong> less than κ + . Then ⋃ A ′ < κ + , so by the inductive hypothesis there<br />

is a one-one regressive function f on A ′ . We can extend f to A by setting f(κ + ) = κ, and<br />

so we get a one-one regressive function defined on A.<br />

Suppose that γ is singular. Let 〈µ ξ : ξ < cf(γ)〉 be a strictly increasing continuous<br />

sequence of infinite <strong>cardinals</strong> with supremum γ, with cf(γ) < µ 0 . Note then that for every<br />

cardinal λ < γ, either λ < µ 0 or else there is a unique ξ < cf(γ) such that µ ξ ≤ λ < µ ξ+1 .<br />

For every ξ < cf(γ) we can apply the inductive hypothesis to A ∩ µ ξ to get a one-one<br />

regressive function g ξ with domain A ∩ µ ξ . We now define f with domain A. In case<br />

cf(γ) = ω we define, for each λ ∈ A,<br />

⎧<br />

g 0 (λ) + 2 if λ < µ 0 ,<br />

⎪⎨ µ ξ + g ξ+1 (λ) + 1 if µ ξ < λ < µ ξ+1 ,<br />

f(λ) = µ ξ if λ = µ ξ+1 ,<br />

⎪⎩ 1 if λ = µ 0 ,<br />

0 if λ = γ ∈ A.<br />

Here the addition is ordinal addition. Clearly f is as desired in this case. If cf(γ) > ω, let<br />

〈ν ξ : ξ < cf(γ)〉 be a strictly increasing sequence of limit ordinals with supremum cf(γ).<br />

Then we define, for each λ ∈ A,<br />

⎧<br />

g ⎪⎨ 0 (λ) + 1 if λ < µ 0 ,<br />

µ<br />

f(λ) = ξ + g ξ+1 (λ) + 1 if µ ξ < λ < µ ξ+1 ,<br />

⎪⎩ ν ξ if λ = µ ξ ,<br />

0 if λ = γ ∈ A.<br />

Clearly f works in this case too.<br />

Finally, suppose that γ is a regular limit cardinal. By assumption, there is a club C<br />

in γ such that C ∩ γ ∩ A = ∅. We may assume that C ∩ ω = ∅. Let 〈µ ξ : ξ < γ〉 be the<br />

strictly increasing enumeration of C. Then we define, for each λ ∈ A,<br />

⎧<br />

⎨g 0 (λ) + 1 if λ < µ 0 ,<br />

f(λ) = µ<br />

⎩ ξ + g ξ+1 (λ) + 1 if µ ξ < λ < µ ξ+1 ,<br />

0 if λ = γ ∈ A.<br />

Clearly f works in this case too.<br />

Lemma <strong>18.</strong>10. Suppose that κ is weakly compact, and S is a stationary subset of κ. Then<br />

there is a regular λ < κ such that S ∩ λ is stationary in λ.<br />

Proof. Suppose not. Thus for all regular λ < κ, the set S ∩ λ is non-stationary in<br />

λ. Let C be the collection of all infinite <strong>cardinals</strong> less than κ. Clearly C is club in κ, so<br />

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