Lecture 4 Notes (PDF) - SFSU Physics & Astronomy
Lecture 4 Notes (PDF) - SFSU Physics & Astronomy
Lecture 4 Notes (PDF) - SFSU Physics & Astronomy
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Solving the problem<br />
• What is known<br />
X f = 3.2 m<br />
V f = 26.0 m/s<br />
Assuming<br />
v 0 = 0 m/s<br />
x 0 = 0 m<br />
x<br />
a<br />
v<br />
To be determined:<br />
(a) t f – time it takes rocket to reach the height x f<br />
(b) a – the rocket’s acceleration<br />
(c) x (t=0.1s)<br />
5<br />
Solution<br />
Starting equation<br />
1 x f<br />
= x<br />
0<br />
+ v<br />
0 t + at<br />
2<br />
v<br />
f<br />
v f<br />
= at a =<br />
t<br />
1<br />
x<br />
f<br />
= v<br />
f<br />
t<br />
2<br />
Part (a)<br />
2x<br />
t =<br />
v<br />
f<br />
f<br />
2<br />
6.2m<br />
=<br />
26m<br />
/ s<br />
Part (b)<br />
v<br />
f<br />
a =<br />
t<br />
Part (c)<br />
1<br />
x(<br />
t = 0.1s)<br />
=<br />
2<br />
= 0.5•<br />
108.3m<br />
/ s<br />
= 0.24s<br />
26m<br />
/ s<br />
= = 108.3m<br />
/ s<br />
0.24s<br />
at<br />
2<br />
2<br />
•(0.1s)<br />
2<br />
2<br />
= 0.54m<br />
6
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