In the World of Mathematics
In the World of Mathematics
In the World of Mathematics
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323. Let AA 1 and CC 1 be angle bisectors <strong>of</strong> triangle ABC (A 1 ∈ BC, C 1 ∈ AB). Straight line<br />
A 1 C 1 intersects ray AC at point D. Prove that angle ABD is obtuse.<br />
(I. Nagel, Evpatoria)<br />
324. Let H be <strong>the</strong> orthocenter <strong>of</strong> acute-angled triangle ABC. Circle ω with diameter AH and<br />
circumcircle <strong>of</strong> triangle BHC intersect at point P ≠ H. Prove that <strong>the</strong> straight line AP pass<br />
through <strong>the</strong> midpoint <strong>of</strong> BC.<br />
325. Solve <strong>the</strong> inequality<br />
|x − 1| + 3|x − 3|+5|x − 5| + . . . + 2009|x − 2009| ≥<br />
(Yu. Biletskyy, Kyiv)<br />
≥2|x − 2| + 4|x − 4| + 6|x − 6| + . . . + 2008|x − 2008|.<br />
(O. Kukush, Kyiv)<br />
326. Let P be arbitrary point inside <strong>the</strong> triangle ABC, ω A , ω B and ω C be <strong>the</strong> circumcircles<br />
<strong>of</strong> triangles BP C, AP C and AP B respectively. Denote by X, Y, Z <strong>the</strong><br />
intersection points <strong>of</strong> straight lines AP, BP, CP with circles ω A , ω B , ω C respectively<br />
(X, Y, Z ≠ P ). Prove that<br />
AP<br />
AX + BP<br />
BY + CP<br />
CZ = 1.<br />
(O. Manzjuk, Kyiv)<br />
327. Some cities <strong>of</strong> <strong>the</strong> country are connected by air flights in both directions. It is known that it is<br />
possible to reach every city from any ano<strong>the</strong>r (probably, with changes) and <strong>the</strong>re are exactly<br />
100 flights from each city. Some m flights have been canceled because <strong>of</strong> bad wea<strong>the</strong>r conditions.<br />
For which maximum m it is still possible to travel between each two cities (probably,<br />
with changes)?<br />
328. Let a and b be rational numbers such that<br />
Volume 14(2008) Issue 3<br />
2<br />
2a + b = 2a b + b<br />
2a − 1<br />
Prove that 1 − 2ab is a square <strong>of</strong> rational number.<br />
(here a ≠ 0, b ≠ 0, b ≠ −2a).<br />
(A. Prymak, Kyiv)<br />
(I. Nagel, Evpatoria)<br />
329. Construct triangle ABC given points O A and O B , which are symmetric to its circumcenter<br />
O with respect to BC and AC, and <strong>the</strong> straight line h A , which contains its altitude to BC.<br />
(G. Filippovskyy, Kyiv)<br />
330. Let O be <strong>the</strong> midpoint <strong>of</strong> <strong>the</strong> side AB <strong>of</strong> triangle ABC. Points M and K are<br />
chosen at sides AC and BC respectively such that ∠MOK = 90 ◦ . Find angle ACB, if<br />
AM 2 + BK 2 = CM 2 + CK 2 .<br />
(I. Fedak, Ivano-Frankivsk)<br />
331. Do <strong>the</strong>re exist positive integers a and b such that<br />
a) 4a 3 − 53a − 1 = 10 2b ; b) 4a 3 − 53a − 1 = 10 2b−1 ?<br />
(O. Makarchuk, Kirovograd)<br />
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