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For Peer Review Only - TARA

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Page 27 of 69<br />

Molecular Physics<br />

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before connecting to each other. Even in this case, an equivalent transition state, in<br />

which one more phosphine is on the metal, has been located: this structure is 4.1 kcal<br />

mol -1 less stable than TS19. Once again, even if bonded to the metal, an additional<br />

phosphine does not afford an energy stabilization. After the discussed C-C bond<br />

formation, the system evolves to an intermediate, M25, in which the palladium is<br />

<strong>For</strong> <strong>Peer</strong> <strong>Review</strong> <strong>Only</strong><br />

bearing three ligands only: one phosphine, one chlorine atom and the allyl carbonyl<br />

chain. The CO unit has inserted into the carbon-palladium bond and now the metal is<br />

linked to a 4-carbon chain. In spite of the unsaturated metal coordination sphere, this<br />

complex is more stable than all the other structures determined so far, because of the<br />

formation of a new carbon-carbon bond (M25 lies 0.4 kcal mol -1 below the AL and<br />

5.1 lower than the previous intermediate). At this point, there is space for an easy<br />

approach of a triphenylphosphine to the unsaturated palladium (TS20, activation<br />

energy= 0.4 kcal mol -1 ) that brings the system to the already discussed M18. The<br />

subsequent steps are obviously those already described in the section 3.B.1 and<br />

terminates the catalytic cycle. It is worth mentioning that a transition state for an<br />

approach of the chloroallyl unit to the palladium in the initial Pd(PPh 3 ) 3 complex that<br />

would eventually lead directly to its oxidation has been found. This transition state<br />

would lead to M24 (see Scheme 8), after the concerted breaking of the allylic carbonchlorine<br />

bond and the formation of the relative carbon-palladium and chlorinepalladium<br />

bonds. Additionally, one phosphine leaves the metal. Although this<br />

transition state exists, it is located very high in energy compared to any other points<br />

discussed so far: 39.6 kcal mol -1 . It is evident that there is a high cost of energy for the<br />

system when a single carbon atom is involved in the breaking of a bond and the<br />

simultaneous forming of an interaction with the palladium. In all the cases of carbonmetal<br />

σ-bond formation described above, the carbon atom was previously involved in<br />

URL: http://mc.manuscriptcentral.com/tandf/tmph

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