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A New Generalized Matrix Inverse Method for Balancing Chemical ...

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A <strong>New</strong> <strong>Generalized</strong> <strong>Matrix</strong> <strong>Inverse</strong> <strong>Method</strong> <strong>for</strong> <strong>Balancing</strong> <strong>Chemical</strong> Equations and their Stability 109<br />

Corollary 4.9. Let A∈. Then stab(A) < 0 ⇔ m(A) < 0 <strong>for</strong><br />

some Lozinskiĭ measure m on n .<br />

More results <strong>for</strong> stability criteria are obtained in works<br />

[142, 143].<br />

5. An Application of the Main Results<br />

In this section will be applied above method on many chemical<br />

equations <strong>for</strong> their balancing. All chemical equations balanced<br />

here appear first time in professional literature and they are<br />

chosen with an intention to be avoided to date all well known<br />

chemical equations which were repeated many times in the<br />

chemical journals <strong>for</strong> explanation of certain particular techniques<br />

<strong>for</strong> balancing of some chemical equations using only<br />

atoms with integer oxidation numbers.<br />

1º First we will consider an infeasible reaction, i. e., the<br />

case when the nullity of the reaction matrix is zero.<br />

matrix is one. Here we will balance many special chemical<br />

equations with a goal to show the power of the offered mathematical<br />

method.<br />

Example 5. 2. Consider this equation<br />

x 1 [4Yb(CN) 3·3Yb(CN) 2 ] + x 2 CsRu(CN) 2 F 2 (5. 2)<br />

+ x 3 CsRu(CN) 4 + x 4 CsHF 2 + x 5 [PtF 3·7H 2 O]<br />

= x 6 [Pt(NH 3 ) 2 (C 5 H 4 ON)] 2 (NO 3 ) 2·2H 2 O<br />

+ x 7 Cs 3.99 Yb(CN) 6 + x 8 HRuF 2.97 + x 9 NO 2 .<br />

From the scheme given below<br />

Example 5. 1. Consider chemical equation<br />

x 1 Fe 2 (SO 4 ) 3 + x 2 PrTlTe 3 + x 3 H 3 PO 4 (5. 1)<br />

= x 4 Fe(H 2 PO 4 ) 2·H 2 O + x 5 Pr 2 (SO 4 ) 3 + x 6 Tl 1.99 (SO 3 ) 3<br />

+ x 7 Te 2 O 3 + x 8 H 2 O.<br />

The reaction matrix<br />

2 0 0 -1 0.00 0.00 0 0<br />

3 0 0 0 -3.00 -3.00 0 0<br />

12 0 4 -9 -12.0 -9.00 -3 -1<br />

0 1 0 0 -2.00 0.00 0 0<br />

0 1 0 0 0.00 -1.99 0 0 .<br />

0 3 0 0 0.00 0.00 -2 0<br />

0 0 3 -6 0.00 0.00 0 -2<br />

0 0 1 -2 0.00 0.00 0 0<br />

is obtained from this scheme<br />

is derived the reaction matrix<br />

⎡ 7.00 0 0 0 0.00 0.00 -1.00 0.00 0 ⎤.<br />

⎢ 18.0 2 4 0 0.00 -10.0 -6.00 0.00 0 ⎥.<br />

⎢ 18.0 2 4 0 0.00 -8.00 -6.00 0.00 -1 ⎥.<br />

⎢ 0.00 1 1 1 0.00 0.00 -3.99 0.00 0 ⎥.<br />

A = ⎢ 0.00 1 1 0 0.00 0.00 0.00 -1.00 0 ⎥.<br />

⎢ 0.00 2 0 2 3.00 0.00 0.00 -2.97 0 ⎥.<br />

⎢ 0.00 0 0 1 14.0 -24.0 0.00 -1.00 0 ⎥.<br />

⎢ 0.00 0 0 0 1.00 -2.00 0.00 0.00 0 ⎥.<br />

⎣ 0.00 0 0 0 7.00 -10.0 0.00 0.00 -2 ⎦.<br />

The rank of the above matrix is r = 8. Since the nullity of<br />

the reaction matrix is k = n - r = 8 - 8 = 0, then we have only a<br />

trivial solution x = 0, that means that the reaction is infeasible.<br />

2º Next, we will consider the case when the chemical reaction<br />

is feasible and is unique, i. e., the nullity of its reaction<br />

The rank of the above matrix is r = 8. Since the nullity of<br />

the reaction matrix is k = n - r = 9 - 8 = 1, then we have a nontrivial<br />

solution x ≠ 0, that means that the reaction is feasible.<br />

Singular value decomposition of the matrix A is given by<br />

the expression A = USV T , where

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