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Electrochemistry (Ch 17) - AP Chemistry

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4/1/2011<br />

CONCENTRATION DEPENDENCE<br />

• For the reaction,<br />

Cu(s) + 2 Ce 4+ (aq) Cu 2+ (aq) + 2 Ce 3+ (aq)<br />

has a potential of 1.36 V under standard conditions (1 M<br />

concentrations all)<br />

– What if [Ce 4+ ] is greater than 1 M <br />

• Le <strong>Ch</strong>âtelier's principle predicts that the forward reaction will be favored,<br />

increasing the cell potential.<br />

– What if [Cu 2+ ] or [Ce 3+ ] is increased<br />

• Cell potential is decreased<br />

THE EFFECTS OF CONCENTRATION ON E<br />

• For the cell reaction,<br />

2 Al(s) + 3 Mn 2+ (aq) 2 Al 3+ (aq) + 3 Mn(s) E = 0.48 V<br />

predict whether E cell is larger or smaller than E cell for the<br />

following cases<br />

– [Al 3+ ] = 2.0 M, [Mn 2+ ] = 1.0 M<br />

• E cell < 0.48 V<br />

– [Al 3+ ] = 1.0 M, [Mn 2+ ] = 3.0 M<br />

• E cell > 0.48 V<br />

<strong>Ch</strong> <strong>17</strong> - <strong>Electrochemistry</strong> 31<br />

<strong>Ch</strong> <strong>17</strong> - <strong>Electrochemistry</strong> 32<br />

CONCENTRATION CELLS<br />

• A galvanic cell in which both<br />

compartments have the same<br />

components but at different<br />

concentrations is called a<br />

concentration cell (typically<br />

with small voltages)<br />

– What is the potential of this cell<br />

and what is the direction of<br />

electron flow<br />

– The relevant half-reaction is,<br />

Ag + + e - Ag<br />

E = 0.80 V<br />

CONCENTRATION CELLS<br />

• The electrons will flow in the<br />

direction that will equalize the<br />

concentrations of Ag + in the<br />

two compartments<br />

– Accomplished by transferring<br />

electrons from the 0.1 M Ag +<br />

compartment to the 1 M Ag +<br />

compartment<br />

– This produces more Ag + in the<br />

left compartment and consumes<br />

Ag + in the right compartment<br />

<strong>Ch</strong> <strong>17</strong> - <strong>Electrochemistry</strong> 33<br />

<strong>Ch</strong> <strong>17</strong> - <strong>Electrochemistry</strong> 34<br />

CONCENTRATION CELLS<br />

• Determine the direction of electron flow and designate the anode and<br />

cathode for the cell represented below.<br />

THE NERNST EQUATION<br />

• The concentration dependence of cell potential results directly from the<br />

dependence of free energy on concentration<br />

– Recall, ∆G = ∆G + RT lnQ where Q is the reaction quotient<br />

– Also recall, ∆G = -nFE and ∆G = -nFE<br />

– So, -nFE = -nFE + RT lnQ<br />

• Solving for cell potential,<br />

– Fe 2+ + 2 e - Fe<br />

– Transferring electrons from left (anode) to right (cathode)<br />

– This equation gives the relationship between the cell potential and the concentrations<br />

of the cell components is commonly called the Nernst equation (German chemist<br />

Walther Hermann Nernst, 1864-1941)<br />

– At 25C,<br />

<strong>Ch</strong> <strong>17</strong> - <strong>Electrochemistry</strong> 35<br />

<strong>Ch</strong> <strong>17</strong> - <strong>Electrochemistry</strong> 36<br />

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