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Chapter 9: Einstein and Relativity Theory (319 KB) - D Cassidy Books

Chapter 9: Einstein and Relativity Theory (319 KB) - D Cassidy Books

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3637_<strong>Cassidy</strong>TX_09 6/14/02 12:08 PM Page 423<br />

9.6 RELATIVITY OF TIME 423<br />

Squaring <strong>and</strong> canceling like terms, we<br />

have<br />

c 2 t 2 c 2 t 2 v 2 t 2 .<br />

Now, let’s solve for t:<br />

c 2 t 2 v 2 t 2 c 2 t 2 ,<br />

t 2 (c 2 v 2 ) c 2 t 2 ,<br />

c 2 t 2<br />

t 2 ,<br />

c 2 v 2<br />

t 2<br />

t 2 ,<br />

1 v 2 /c 2<br />

or<br />

t<br />

t ,<br />

1 /c v<br />

2<br />

2<br />

Since 1 v 2 /c 2 is here always less than 1,<br />

the denominator is less than 1, <strong>and</strong> the<br />

fraction is larger than t alone. Thus, the<br />

time interval t registered by the clock as<br />

seen by the stationary observer is “dilated”<br />

compared to the time interval t registered<br />

by the clock as seen by the observer riding<br />

with the clock. In other words, the moving<br />

clock appears to run slower as measured<br />

by the stationary observer than when<br />

the clock is not moving with respect to the<br />

observer. Note also the crucial role of <strong>Einstein</strong>’s<br />

second postulate in this derivation.<br />

Since d is larger than d, t must be larger than t, in order for the ratios on<br />

the right side of both equations to have the same value, c. This means that<br />

the time interval (t) for the round trip of the light pulse, as registered on<br />

the clock as John observes it, is longer than the time interval (t) registered<br />

on the clock as Jane observes it.<br />

The surprising conclusion of this thought experiment (which is really a<br />

deduction from the postulates of relativity theory) is:<br />

Time intervals are not absolute <strong>and</strong> unchanging, but relative. A<br />

clock (such as Jane’s), or any repetitive phenomenon which is moving<br />

relative to a stationary observer appears to the stationary observer<br />

to run slower than it appears to do when measured by the<br />

observer moving with the clock—<strong>and</strong> it appears to run slower the<br />

faster the clock is moving. This is known as time dilation.<br />

Just how much slower does a clock seem when it is moving past an observer<br />

To get the answer, you can use the diagram in Figure 9.10 of John<br />

<strong>and</strong> Jane <strong>and</strong> apply the Pythagorean theorem. After a bit of basic algebra<br />

(see the derivation in the insert), you obtain the exact relationship between<br />

the time elapsed interval registered by a clock that is stationary with respect<br />

to the observer (as in the case of Jane)—call it now T s —<strong>and</strong> the

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