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Binomial distribution - the Australian Mathematical Sciences Institute

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A guide for teachers – Years 11 and 12 • {17}<br />

want Pr(X ≥ 1) ≥ 0.9, since we only need to observe <strong>the</strong> species in one quadrat to know<br />

that it is present in <strong>the</strong> forest. We have<br />

Pr(X ≥ 1) ≥ 0.9 ⇐⇒ Pr(X = 0) ≤ 0.1<br />

⇐⇒ (1 − k) n ≤ 0.1<br />

⇐⇒ n ≥ log e (0.1)<br />

log e (1 − k) .<br />

For example: if k = 0.1, we need n ≥ 22; if k = 0.05, we need n ≥ 45; if k = 0.01, we need<br />

n ≥ 230.<br />

Exercise 4<br />

a<br />

p 0.01 0.05 0.2 0.35 0.5 0.65 0.8 0.95 0.99<br />

µ X 0.2 1 4 7 10 13 16 19 19.8<br />

sd(X ) 0.445 0.975 1.789 2.133 2.236 2.133 1.789 0.975 0.445<br />

b<br />

The standard deviation is smallest when |p−0.5| is largest; in this set of <strong>distribution</strong>s,<br />

when p = 0.01 and p = 0.99. The standard deviation is largest when p = 0.5.<br />

Exercise 5<br />

a<br />

The graph of <strong>the</strong> variance of X as a function of p is as follows.<br />

var(X) = np(1‐p)<br />

<br />

4<br />

<br />

8<br />

0<br />

0.1<br />

0.2<br />

0.3<br />

0.4<br />

0.5<br />

p<br />

0.6<br />

0.7<br />

0.8<br />

0.9<br />

1<br />

Figure 3: Variance of X as a function of p, where X d = Bi(n, p).

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