FMS Actual Paper – 2007 (Memory Based Questions)
FMS Actual Paper – 2007 (Memory Based Questions)
FMS Actual Paper – 2007 (Memory Based Questions)
You also want an ePaper? Increase the reach of your titles
YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.
<strong>–</strong>1 3<br />
1. d Slope of the, line = =<br />
<strong>–</strong>2 2<br />
3<br />
Equation is<br />
y<strong>–</strong>1 3<br />
= or 3x <strong>–</strong> 2y = 1<br />
x<strong>–</strong>1 2<br />
Hence (d) is the correct answer.<br />
<strong>–</strong>1<br />
2. b Slope of the line = = 1<br />
<strong>–</strong>1<br />
3. d<br />
4. c<br />
Answers and Explanations<br />
equation is y<strong>–</strong>2 1<br />
x<strong>–</strong>3 =<br />
or x <strong>–</strong> y = 1<br />
Hence (b).<br />
(0, 4) C<br />
A<br />
(<strong>–</strong>1, <strong>–</strong>1)<br />
y<br />
( )<br />
B(3,<br />
5)<br />
3 1<br />
Slopes of lines AB, BC & AC are , and5 .<br />
2 3<br />
The length of the sides AB, BC and AC are<br />
52 units, 10 units and 26 units.<br />
As. AC 2 + BC 2 < AB 2 ; It is an obtuse triangle. Hence (d).<br />
A<br />
a<br />
60°<br />
h<br />
B D C<br />
a= 3 3units<br />
2 2 2<br />
AB BD AD<br />
= +<br />
2<br />
2 ⎛a⎞ 3 3<br />
or h = a <strong>–</strong> ⎜ ⎟ = a = × ( 3 3)<br />
⎝2⎠ 2 2<br />
or h = 4.5 units. hence (c) is correct.<br />
x<br />
<strong>FMS</strong> ACTUAL PAPER <strong>2007</strong> Page 1<br />
5. b<br />
7 log7 log7 c<br />
log6<br />
= = =<br />
log6 log2+ log3 a+ b<br />
Hence, (b) is correct.<br />
6. c If x lies between 2 and 3 then it is greater than 2 and<br />
less than 3.<br />
7. a<br />
8. a<br />
9. b<br />
10. b<br />
⇒ ( x<strong>–</strong>2) > 0and<br />
(x <strong>–</strong> 3) < 0<br />
⇒ ( x<strong>–</strong>2) ( x<strong>–</strong>3) < 0 . Hence (b) is always correct.<br />
(a) is incorrect and (c) is correct for some values of x,<br />
only.<br />
2<br />
6 x<strong>–</strong>x 0<br />
+ ≥<br />
2<br />
⇒ x <strong>–</strong>x<strong>–</strong>6 ≤0<br />
or ( x+ 2) ( x<strong>–</strong>3) ≤0<br />
⇒<strong>–</strong>2≤x ≤3<br />
Hence (a) is correct.<br />
1<br />
3<br />
+ 2<br />
3<br />
+ 3<br />
3<br />
+ ........12<br />
3<br />
2 2 2 2<br />
1 + 2 + 3 + ........ + 12<br />
2<br />
⎧⎪12( 12+ 1)<br />
⎫⎪<br />
⎨ ⎬<br />
⎪ 2 ⎪ 234<br />
=<br />
⎩ ⎭<br />
=<br />
12 12 1 12 2 1 25<br />
( + ) ( × + )<br />
6<br />
Hence (a) is correct.<br />
2 2<br />
1+° i 1+° i + 2i°<br />
= = =° i<br />
1<strong>–</strong>i° 2 2 1+ 1<br />
( 1+° i )<br />
( 1 ) <strong>–</strong> ( i°<br />
)<br />
2 ( )<br />
100<br />
⎛1+° i ⎞<br />
50<br />
⎜ ⎟ = i° = 1<br />
⎝1<strong>–</strong>i° ⎠<br />
Hence (b) is correct.<br />
6 6<br />
⎛ <strong>–</strong>1+ i 3 ⎞ ⎛ <strong>–</strong>1<strong>–</strong>i 3⎞<br />
=<br />
⎜ ⎟ +<br />
⎜ ⎟<br />
⎝ 2 ⎠ ⎝ 2 ⎠<br />
( +<br />
2<br />
)<br />
( ) ( )<br />
( )<br />
( ) ( )<br />
⎛ ⎞ ⎛ ⎞<br />
⎜ 1 i 3 ⎟ ⎜ 1<strong>–</strong>i 3 ⎟<br />
= ⎜ ⎟ +<br />
2 2 ⎜ 2 2⎟<br />
⎜ 1 <strong>–</strong> i 3 ⎟ ⎜ 1 <strong>–</strong> i 3 ⎟<br />
⎝ ⎠ ⎝ ⎠