Abstract Algebra and Algebraic Number Theory
Abstract Algebra and Algebraic Number Theory
Abstract Algebra and Algebraic Number Theory
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We define norm,N E/F (α) , trace, T E/F (α) <strong>and</strong> characteristic polynomial,char E/F (x),<br />
of α, relative to extension E/F , as follows<br />
N E/F (α) = det m(α)<br />
T E/F (α) = trace m(α) <strong>and</strong> char E/F (α)(x) = det [xI−A(α)]<br />
Proposition 4.2.1. char E/F (α)(x) = [min α,F (x)] r , where r = [E : F (α)].<br />
Corollary. Let [E : F ] = n <strong>and</strong> [F (α) : F ] = d. Let α 1 , α 2 , ...., α d be the<br />
roots of min α,F (x), counting multiplicity, in a splitting field. Then<br />
N(α) = ( d ∏<br />
i=1<br />
α i<br />
)<br />
, T (α) =<br />
(n<br />
d<br />
d∑ )<br />
α i ,<br />
i=1<br />
{ ∏<br />
d<br />
char(α)(x) = (x − α i ) } n d<br />
i=1<br />
Proof. Result follows from the above theorem <strong>and</strong> from the fact that<br />
.<br />
char(α)(x) = x n − T (α)x n−1 + ... + (−1) n N(α)<br />
Proposition 4.2.2. Let E/F be a separable extension of degree n, let<br />
σ 1 , σ 2 , ..., σ n be the distinct F-embedding of E into an algebraic closure of<br />
E, or equally well into a normal extension L of F containing E. Then<br />
N E/F (α) =<br />
n∏<br />
σ i (α), T E/F (α) =<br />
i=0<br />
char E/F (α)(x) =<br />
n∑<br />
σ i (α)<br />
i=0<br />
n∏<br />
(x − σ i (α))<br />
Proposition 4.2.3. Let us consider AKLB setup. Let α ∈ B, then the<br />
coefficient of min α,F (x) <strong>and</strong> char E/F (α)(x) are integral over A, In particular<br />
T L/K (α) <strong>and</strong> N L/K (α) are integral over A. If A is integrally closed then<br />
coefficient belongs to A.<br />
Corollary. An algebraic integer a ∈ Q must in fact belong to Z.<br />
Proposition 4.2.4. In AKLB setup, let α ∈ L, then there is a non zero<br />
element a ∈ A <strong>and</strong> β ∈ B such that α = β a<br />
, i.e. L is a fraction field of B.<br />
Proposition 4.2.5. In AKLB setup, there is a basis of L/K consisting<br />
entirely the elements of B.<br />
i=0<br />
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