September 2002 - Information Theory Society - the IEEE Information ...
September 2002 - Information Theory Society - the IEEE Information ...
September 2002 - Information Theory Society - the IEEE Information ...
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13<br />
preparing a proposal which outlines <strong>the</strong> criteria for <strong>the</strong><br />
award for <strong>the</strong> next BOG meeting.<br />
13. <strong>IEEE</strong> Headquarters decision to not provide full membership<br />
support to residents of Burma, Cuba, Iran, Libya and<br />
Sudan was discussed (see http://www.ieeesanctions.org/).<br />
An explanation of <strong>the</strong> <strong>IEEE</strong> position will be requested.<br />
14. Tom Fuja thanked Sergio Verdú for making arrangements<br />
for <strong>the</strong> Board Meeting. He announced that <strong>the</strong> Annual<br />
Meeting of <strong>the</strong> <strong>Society</strong> will be held at <strong>the</strong> Hotel<br />
Alpha-Palmiers in Lausanne, Switzerland on Sunday,<br />
June 30, beginning at 12:00 PM (noon).<br />
15. The meeting was adjourned at 2:10 PM.<br />
New Books (correction)<br />
Advanced <strong>Theory</strong> of Signal Detection: Weak Signal Detection in Generalized Observations<br />
by Iickho Song, Jinsoo Bae, and Sun Yong Kim, Springer-Verlag, <strong>2002</strong>, 395 pp., EUR99.95, ISBN<br />
3-540-43064-4<br />
http://www.springer.de<br />
Contents: Preliminaries; Locally Optimum Detection of Signal; Signal Detection with Signs and Ranks; Detection in<br />
Weakly-Dependent Noise Model; Detection with Fuzzy Observations.<br />
GOLOMB’S PUZZLE COLUMN<br />
Placing Pentominoes on Boards — Solutions<br />
1. The first task was to find <strong>the</strong> inequivalent placements of<br />
a pentomino ona5×7board such that <strong>the</strong> rest of <strong>the</strong> board<br />
⎛ ⎞<br />
⎜ ⎟<br />
can be tiled with ten “right trominoes”<br />
's<br />
⎜<br />
⎟ .<br />
⎝ ⎠<br />
Note that a right tromino covers at most one of <strong>the</strong> twelve<br />
“dotted squares” on <strong>the</strong> 5 × 7 board. Hence<br />
<strong>the</strong> pentomino must cover at least two of <strong>the</strong> dotted<br />
squares in order for <strong>the</strong> rest to be tiled by ten right<br />
trominoes. (Each pentomino can be placed to cover two of<br />
<strong>the</strong> dotted squares, but only <strong>the</strong> I and <strong>the</strong> V are able to<br />
cover three.)<br />
The 2×3 rectangle,<br />
, can be tiled in two different<br />
ways by two right trominoes, so in <strong>the</strong> solutions<br />
which follow we leave this region undivided.<br />
Here are <strong>the</strong> 50 solutions I have found. (There may be o<strong>the</strong>rs<br />
that I missed.)<br />
<strong>September</strong> <strong>2002</strong><br />
<strong>IEEE</strong> <strong>Information</strong> <strong>Theory</strong> <strong>Society</strong> Newsletter