Ksp Problem Set - Widener University

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.0.3295 g BaF 2 dissolves in 250.0 mL of water at 25 °C mass := 0.3295⋅gm V := 250.0⋅mL MW BaF2 := ( 137.329 + 18.998⋅2) ⋅gm⋅ mole − 1 mass mole BaF2 := mole BaF2 = 1.879 × 10 − 3 mol MW BaF2 M mole BaF2 := M 7.517 10 − 3 − 1 = × mole⋅liter V The molar solubility is simply the concentration of the solution at equlibrium: M 7.517 × 10 − 3 − 1 = mole⋅liter Since BaF 2 --> Ba 2+ + 2 F - K sp_BaF2 := 4⋅M 3 K sp_BaF2 = 1.699 × 10 − 6 ⎛ ⎜ ⎝ mole liter ⎞ ⎟ ⎠ 3 ksp_a.mcd 3/25/2004 2 S.E. Van Bramer svanbram@science.widener.edu
c.4.807*10-4 g AgCl dissolves in 250.0 mL of water at 25 °C mass := 4.807⋅10 − 4 ⋅gm V := 250.0⋅mL MW AgCl := ( 107.8682 + 35.4527) ⋅gm⋅ mole − 1 mass mole AgCl := mole AgCl = 3.354 × 10 − 6 mol MW AgCl M mole AgCl := M 1.342 10 − 5 − 1 = × mole⋅liter V The molar solubility is simply the concentration of the solution at equlibrium: M 1.342 × 10 − 5 − 1 = mole⋅liter Since AgCl --> Ag+ + Cl- K sp_AgCl := M 2 K sp_AgCl = 1.8 × 10 − 10 ⎛ ⎜ ⎝ mole liter ⎞ ⎟ ⎠ 2 ksp_a.mcd 3/25/2004 3 S.E. Van Bramer svanbram@science.widener.edu
Page 1: Ksp Problem Set By S.E. Van Bramer
Page 5 and 6: 2.Use the K sp values calculated ab
Page 7 and 8: 3.Use the K sp values calculated ab
Page 9 and 10: c.The mass of AgCl that will dissol
Page 11 and 12: 4.Use the K sp values calculated in
Page 13 and 14: c.75.0 mL of 0.015 M silver nitrate
Page 15: Since Calcium Fluoride is insoluble

Ksp Problem Set - Widener University

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