NARAYANA IIT ACADEMY JEE MAIN â 2013 - Narayana Group
NARAYANA IIT ACADEMY JEE MAIN â 2013 - Narayana Group
NARAYANA IIT ACADEMY JEE MAIN â 2013 - Narayana Group
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(1) Methylisocyanate (2) Methylamine (3) Ammonia (4) Phosgene<br />
Key : 1<br />
Sol: (1)<br />
MIC was responsible for Bhopal gas tragedy.<br />
60. Experimentally it was found that a metal oxide has formula M<br />
0.98<br />
O . Metal M, is present as<br />
2<br />
M and<br />
3<br />
M <br />
3<br />
M <br />
in its oxide. Fraction of the metal which exists as would be<br />
(1) 7.01 % (2) 4.08 % (3) 6.05% (4) 5.08 %<br />
Key : 2<br />
Sol: (2)<br />
3<br />
Let the number of M and<br />
x y 0.98 ….(i)<br />
3x<br />
2y<br />
2 ….(ii)<br />
3<br />
No. of M ion = 0.04<br />
2<br />
And M ion = 0.94<br />
So percentage of<br />
2<br />
M ions be x and y respectively<br />
3<br />
M ion 0.04 100 4.08%<br />
0.98 <br />
MATHEMATICS<br />
61. Distance between two parallel planes 2x + y + 2z = 8 and 4x + 2y + 4z + 5 = 0 is<br />
(1) 3 2<br />
(2) 5 2<br />
(3) 7 2<br />
(4) 9 2<br />
Key. (3)<br />
Sol: Required distance =<br />
5<br />
8<br />
2 7<br />
<br />
2 2 2<br />
2 1 2 2<br />
62. At present, a firm is manufacturing 2000 items. It is estimated that the rate of change of<br />
dP<br />
production P w.r.t. additional number of workers x is given by 100 12<br />
dx<br />
x.<br />
If firm<br />
employs 25 more workers, then the new level of production of items is<br />
(1) 2500 (2) 3000 (3) 3500 (4) 4500<br />
Key. (3)<br />
<br />
Sol: (100 12 x)<br />
dx <br />
dp<br />
24 3/2<br />
100x x P C<br />
3<br />
when x = 0 P = 2000<br />
P = 2000 + 100 x -<br />
As x is 25<br />
P = 3500<br />
24<br />
3 x<br />
3/2<br />
<strong>NARAYANA</strong> <strong>IIT</strong> <strong>ACADEMY</strong> <strong>JEE</strong> <strong>MAIN</strong> – <strong>2013</strong>