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Hui's reference material on Markov chains (pdf)

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epresentati<strong>on</strong> E(N i (k)|X 0 = i) = ∑ k<br />

l=0 P l (i, i), we obtain<br />

0 = lim<br />

k→∞<br />

∑ k<br />

l=0 P l (i, i)<br />

k<br />

≥ lim<br />

k→∞<br />

∑ k−m−n<br />

l=0<br />

P l (j, j)<br />

· P n (i, j)P m (j, i)<br />

k<br />

k − m − n<br />

= lim<br />

·<br />

k→∞ k<br />

∑ k−m−n<br />

l=0<br />

P l (j, j)<br />

· P n (i, j)P m (j, i)<br />

k − m − n<br />

∑ k<br />

l=0<br />

= lim<br />

P l (j, j)<br />

· P n (i, j)P m (j, i)<br />

k→∞ k<br />

= P n (i, j)P m (j, i)<br />

m j<br />

and thus m j = ∞, which signifies the null recurrence of j.<br />

□<br />

Thus we can call a communicati<strong>on</strong> class positive recurrent or null recurrent.<br />

In the former case, a c<strong>on</strong>structi<strong>on</strong> of a stati<strong>on</strong>ary distributi<strong>on</strong> is given in<br />

Theorem 13 Let i ∈ E be positive recurrent and define the mean first visit time<br />

m i := E(τ i |X 0 = i). Then a stati<strong>on</strong>ary distributi<strong>on</strong> π is given by<br />

π j := m −1<br />

i ·<br />

∞∑<br />

P(X n = j, τ i > n|X 0 = i)<br />

n=0<br />

for all j ∈ E. In particular, π i = m −1<br />

i<br />

communicati<strong>on</strong> class bel<strong>on</strong>ging to i.<br />

Proof: First of all, π is a probability measure since<br />

∑<br />

j∈E n=0<br />

∞∑<br />

P(X n = j, τ i > n|X 0 = i) =<br />

and π k = 0 for all states k outside of the<br />

=<br />

∞∑ ∑<br />

P(X n = j, τ i > n|X 0 = i)<br />

n=0 j∈E<br />

∞∑<br />

P(τ i > n|X 0 = i) = m i<br />

n=0<br />

14

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