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Rationals Countability and Cantor's Proof - Gauge-institute.org

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<strong>Gauge</strong> Institute, February 2006<br />

H. Vic Dannon<br />

<strong>and</strong> there are in all 1 elements ( , ) for which ,<br />

namely:<br />

(1, 1) , (2, 2) ,…, ( 1,1) .<br />

In this sequence imagine first the element (1,1) , for which 2 ,<br />

put , then the two elements for which 3 , then the three<br />

elements for which 4 ,<br />

<strong>and</strong> so on. Thus, we get all the elements ( , ) in a simple series:<br />

(1,1); (1, 2), (2,1); (1,3) , (2, 2), (3,1); (1, 4), (2,3) ,…,<br />

<strong>and</strong> here, as we easily see, the element ( , ) comes at the th<br />

place, where<br />

The variable<br />

(9)<br />

( 1)( 2)<br />

.<br />

2<br />

takes every numerical value 1,2,3,... , once.<br />

Consequently, by means of (9), a reciprocally univocal relation<br />

subsists between the aggregates { }<br />

<strong>and</strong> {( , )}.”<br />

Clearly, the variable takes several times some of numerical<br />

value 1,2,3,..., The mapping is not one-one.<br />

We have,<br />

1, 1, 1 , <strong>and</strong> (1,1) 1.<br />

1, 2 , 2 , <strong>and</strong> (1, 2) 2 .<br />

2 , 1, 2 , <strong>and</strong> (2,1) 2 .<br />

1 , 3 , 4 , <strong>and</strong> (1,3) 4 .<br />

2 , 2 , 4 , <strong>and</strong> (2, 2) 4.<br />

2

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