電磁波 Maxwellの方程式

E = f ( z− ct) + f ( z+
ct)
x
1 2
1
H
y
= { f1( z−ct) − f2( z+
ct)
}
η0
1
8
c= = 3×
10 ( m/ s)
µε
η
∂ E
∂z
2 2
x
x
− µε
2 0 0
= 0
2
µ
0 0
0
0
= ≅ ≅
ε0
∂ E
∂t
376.6 120π
2004/10/29 GPR 19
E = f ( z− ct) + f ( z+
ct)
x
1 2
z− ct = constant
z=constant + c
∂ z = c
∂t
2004/10/29 GPR 20
Ex
= f1( z − ct) + f2( z + ct)
1
H
y
= { f1( z−ct) − f2( z+
ct)
}
η
0
η
µ
0
0
= ≅ ≅
ε0
376.6 120π
− jkz + jkz jωt
{( 1 2 ) }
E (,) zt = Re Ae + Ae e
x
= A cos( ωt− kz) + A cos( ωt+
kz)
1 2
ωt− kz = aconstant
2004/10/29 GPR 21
2004/10/29 GPR 22
9.2
E e k
(1)
( x, t) = E0
cos( ⋅x−ωt)
k ⋅x
−ωt
α
k⋅ r= α + ωt
r cosθ
θ
r
k
2004/10/29 GPR 23
t = t 1
k⋅ r = α + ωt (2.42)
1
r
k
2004/10/29
GPR 24