Energy balance around the II condenser
Energy balance around the II condenser
Energy balance around the II condenser
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<strong>Energy</strong> <strong>balance</strong> <strong>around</strong> <strong>the</strong> Benzene Column:<br />
Since water is added as washing liquid to <strong>the</strong> extracted aromatic stream, <strong>the</strong>re will be a<br />
considerable temperature drop in <strong>the</strong> system and fur<strong>the</strong>r more <strong>the</strong> enrgy losses in clay<br />
treater and separator also contributes to <strong>the</strong> temperature drop. ∴Assume <strong>the</strong> feed<br />
temperature to <strong>the</strong> Benzene column = 98 o C and <strong>the</strong> refference temperature is taken as<br />
=0 o C<br />
∴(Cp) B = 1.856 kJ/kg.K<br />
(Cp) T = 1.809 kj/kg. K<br />
(Cp) X = 1.841 kJ/kg.K<br />
∴ (Cp) avg. = Σ (x i x Cp i )<br />
and,<br />
= 1.825 kJ/kg.K<br />
(λ)B = 389.5 kJ/kg<br />
(λ)T = 391.3 kJ/kg<br />
(λ)X = 396.2 kJ/kg<br />
Now assuming <strong>the</strong> Reflux Ratio as;<br />
R = 1.2<br />
∴The flow rate to <strong>the</strong> <strong>condenser</strong> = ( R + 1 ) D<br />
= (1.2 + 1) 1.014<br />
= 2.2308 kg/s<br />
∴The heat load on <strong>the</strong> <strong>condenser</strong>;<br />
Qc = m x λ<br />
= 868.89 KW<br />
To find Q b;