Fluids at rest.pdf

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Example 4 (Cont.): A 2-kg 2brass block isattached to a string and submerged underwater.Now find the the tension in the rope.F B = 2.25 NF B + T = mgT= mg -F BT = (2 kg)(9.8 m/s 2 ) - 2.25 NT = 19.6 N - 2.25 NT = 17.3 NThis force is sometimes referred toas the apparent weight.TmgF B = gVForcediagram
Floating objects:When an object floats, partially submerged, the buoyantforce exactly balances the weight of the object.F BF B = f gV fm x g = x V x g f gV f = x V x gmgFloating Objects: f fV f f= x xV xxIf V f is volume of displacedwater V wd , the relative densityof an object x is given by:Relative Density:xVwdr Vwx
Page 1 and 2: Chapter 15A - Fluids at RestA Power
Page 3 and 4: Objectives: After completing thismo
Page 5 and 6: Example 1: The density of steel is
Page 7 and 8: PressurePressure is the ratio of a
Page 9 and 10: Fluid PressureA liquid or gas canno
Page 11 and 12: Pressure vs. Depth in FluidPressure
Page 13 and 14: Properties of Fluid Pressure• The
Page 15 and 16: Atmospheric PressureOne way to meas
Page 17 and 18: Pascal’s s LawPascal’s Law: An
Page 19 and 20: Archimedes’ Principle• An objec
Page 21: Example 4: A 2-kg 2brass block is a
Page 25 and 26: Problem Solving Strategy1. Draw a f
Page 27 and 28: Problem Strategy (Cont.)6. 6. For a
Page 29 and 30: Summary (Cont.)Pascal’sLaw:FAinin

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