Capacitor Circuits.pdf

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Example 3 (Cont.) Find the total charge Q T .C e e= 6 F24 V C 1 C 24 FC 33 F6 FQ = CV = (6 F)(24 V)Q T T= 144 C24 V4 FC 124 VC 3,6 2 FC e 6 F
Example 3 (Cont.) Find the charge Q 4 andvoltage V 4 across the the 4F 4 F capacitor24 V C 1 C 24 FC 33 F6 FV 44 = V T T= 24 24VQ 4 = (4 F)(24 V)Q 44 = 96 96 CThe remainder of the charge: (144 C – 96 C)is on EACH of the other capacitors. (Series)Q 33 = Q 66 = 48 CThis can also be found fromQ = C 3,6 3,6V 3,6 3,6= (2 F)(24 V)
Page 2 and 3: Objectives: After completing thismo
Page 4 and 5: Series CircuitsCapacitors or other
Page 6 and 7: Voltage on Capacitors in SeriesSinc
Page 8 and 9: Example 1. Find the equivalent capa
Page 10 and 11: Example 1 (Cont.): What is the tota
Page 12 and 13: Short Cut: Two Series CapacitorsThe
Page 14 and 15: Equivalent Capacitance: ParallelPar
Page 16 and 17: Example 2 (Cont.) Find the total ch
Page 20 and 21: Example 3 (Cont.) Find the voltages
Page 22 and 23: Summary: Parallel CircuitsCen Ci1iQ

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