Integrating sinx & cosx
Integrating sinx & cosx
Integrating sinx & cosx
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π1 st area = ∫ <strong>sinx</strong> dx0= [ -<strong>cosx</strong> ] 0π= -cosπ - (- cos0)= -(-1) – ( -1)= 23π/ 22nd area = ∫ <strong>sinx</strong> dxπ= [ -<strong>cosx</strong> ]π3π/ 2= -cos 3 π / 2- (- cos π)= 0 - 1= -1 (actual area = 1)So total area = 2 + 1 = 3units 2alternativelyBy symmetry,2 nd area = ½ of first = 1 etc.
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