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Integration by substitution - Mathcentre

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ExampleSupposewewishtoevaluateBywritingtheintegrandasf(u) = 1 √ u, g(x) = 2x 2 + 1and g ′ (x) = 4x.∫4x√2x2 + 1 dx∫1√2x2 + 1 ·4xwenotethatittakestheformf(g(x))g ′ (x)dxwhereThe<strong>substitution</strong> u = g(x) = 2x 2 + 1transformstheintegralto∫ ∫1f(u) du = √ du uThisisevaluatedtogive∫1√ udu =∫u −1/2 du= 2u 1/2 + cFinally,using u = 2x 2 + 1toreverttotheoriginalvariablegives∫4x√2x2 + 1 dx = 2(2x2 + 1) 1/2 + corequivalentlyExampleSupposewewishtofind∫ sin√ x√ xdx.2 √ 2x 2 + 1 + cConsiderthe<strong>substitution</strong> u = √ x.Thendu =( ) dudxdxsothat= 1 2 x−1/2 dx==12x 1/2dx12 √ x dx∫ √ ∫sin x√ dx = 2 xsin u dufromwhich∫2sin u du = −2 cosu + c= −2 cos √ x + cWecanalsomakethefollowingobservations:theintegrandcanbewrittenintheform sin √ x ·1√ x.www.mathcentre.ac.uk 8 c○mathcentre2009

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