DC-AC Power Inverter Pure Sine Wave PST-1500 ... - DonRowe.com

SECTION 2 | General Informationeffect is a tendency to cancel each other. Hence, in a circuit containing both inductancesand capacitances, the net Reactance (X) will be equal to the difference between thevalues of the inductive and capacitive reactances. The net Reactance (X) will be inductiveif X L> X Cand capacitive if X C> X L.Impedance, Z: It is the vectorial sum of Resistance and Reactance vectors in a circuit.Active Power (P), Watts: It is denoted as “P” and the unit is “Watt”. It is the power thatis consumed in the resistive elements of the load. A load will require additional ReactivePower for powering the inductive and capacitive elements. The effective power requiredwould be the Apparent Power that is a vectorial sum of the Active and Reactive Powers.Reactive Power (Q), VAR: Is denoted as “Q” and the unit is VAR. Over a cycle, this poweris alternatively stored and returned by the inductive and capacitive elements of the load.It is not consumed by the inductive and capacitive elements in the load but a certainvalue travels from the AC source to these elements in the (+) half cycle of the sinusoidalvoltage (Positive value) and the same value is returned back to the AC source in the (-)half cycle of the sinusoidal voltage (Negative value). Hence, when averaged over a spanof one cycle, the net value of this power is 0. However, on an instantaneous basis, thispower has to be provided by the AC source. Hence, the inverter, AC wiring and over currentprotection devices have to be sized based on the combined effect of the Active andReactive Powers that is called the Apparent Power.Apparent (S) Power, VA: This power, denoted by "S", is the vectorial sum of the ActivePower in Watts and the Reactive Power in “VAR”. In magnitude, it is equal to the RMSvalue of voltage “V” X the RMS value of current “A”. The Unit is VA. Please note thatApparent Power VA is more than the Active Power in Watts. Hence, the inverter, AC wiringand over current protection devices have to be sized based on the Apparent Power.Power Factor, (PF): It is denoted by “PF” and is equal to the ratio of the Active Power(P) in Watts to the Apparent Power (S) in VA. The maximum value is 1 for resistive typesof loads where the Active Power (P) in Watts = the Apparent Power (S) in VA. It is 0 forpurely inductive or purely capacitive loads. Practically, the loads will be a combination ofresistive, inductive and capacitive elements and hence, its value will be > 0