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Fluids in motion.pdf

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Strategies (Cont<strong>in</strong>ued)P gh ½v P gh ½v2 21 1 1 2 2 2• For a stationary fluid, v 1 = v 2 and we have:P P = g(h 22 -h 11 ))h = 1000kg/m 3• For a horizontal pipe, h 1 = h 2 and we obta<strong>in</strong>:P P ½v ½v2 21 2 2 1

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