11.07.2015 Views

Chapter 16 Partial Differentiation

Chapter 16 Partial Differentiation

Chapter 16 Partial Differentiation

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½º¿ÈÖØÐ ÖÒØØÓÒ<strong>16</strong>.3 <strong>Partial</strong> <strong>Differentiation</strong> 369When we first considered what the derivative of a vector function might mean, there wasreally not much difficulty in understanding either how such a thing might be computed orwhat it might measure. In the case of functions of two variables, things are a bit harderto understand. If we think of a function of two variables in terms of its graph, a surface,there is a more-or-less obvious derivative-like question we might ask, namely, how “steep”is the surface. But it’s not clear that this has a simple answer, nor how we might proceed.We will start with what seem to be very small steps toward the goal; surprisingly, it turnsout that these simple ideas hold the keys to a more general understanding.86420−2−3−1−2 0x−1102132−3Figure <strong>16</strong>.3.1 f(x,y) = x 2 +y 2 , cut by the plane x+y = 1 (AP)Imagine a particular point on a surface; what might we be able to say about how steepit is? We can limit the question to make it more familiar: how steep is the surface in aparticular direction? What does this even mean? Here’s one way to think of it: Supposewe’re interested in the point (a,b,c). Pick a straight line in the x-y plane through thepoint (a,b,0), then extend the line vertically into a plane. Look at the intersection of theplane with the surface. If we pay attention to just the plane, we see the chosen straightline where the x-axis would normally be, and the intersection with the surface shows up asa curve in the plane. Figure <strong>16</strong>.3.1 shows the parabolic surface from figure <strong>16</strong>.1.2, exposingits cross-section above the line x+y = 1.

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