Electromagnetic Induction

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Calculating Flux When Area isNot Perpendicular to FieldThe flux penetrating thearea A when the normalvector n makes an angleof with the B-fieldis:BAcosABnThe angle is the complement of the angle that theplane of the area makes with B field. (Cos( = Sin )
Example 1: A current loop has an area of 40 cm 2and is placed in a 3-T B-field at the given angles.Find the flux through the loop in each case.x x x xx x x xAx x x xx x x xnnnA = 40 cm 2 (a) = 0 0 (b) = 90 0 (c) = 60 0(a) = BA cos 0 0 = (3 T)(0.004 m 2 )(1); 12.0 mWb(b) = BA cos 90 0 = (3 T)(0.004 m 2 )(0); 0 0 mWb(c) = BA cos 60 0 = (3 T)(0.004 m 2 )(0.5); 6.00 mWb
Page 1 and 2: Chapter 31A - ElectromagneticInduct
Page 3 and 4: Induced CurrentWhen a conductor mov
Page 5: Magnetic Flux Density• Magnetic f
Page 9 and 10: Example 2: A coil has 200 turns of
Page 11 and 12: Example 3: Use Lenz’s s law to de
Page 13 and 14: Motional EMF in a WireForce F on ch
Page 15 and 16: The AC Generator• An alternating
Page 17 and 18: Calculating Induced EMFRectangularl
Page 19 and 20: Example 5: An ac generator has 12 t
Page 21 and 22: The Electric MotorIn In a simple el
Page 23 and 24: Example 6: A series-wound dc motor
Page 25 and 26: Summary (Cont.)Lenz’s s law: An A
Page 27 and 28: Summary (Cont.)The ac ac generator
Page 29: CONCLUSION: Chapter 31AElectromagne

Electromagnetic Induction

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