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Trigonometric functions - Mathcentre

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Tocomparethetwographs,wecankeepthesamescaleonthe x-axisandplotbothgraphs.f(x)1x in degrees060xx in radiansWith xindegrees,thefunction f(x) = sin xhasnotreached1bytheright-handsideofthegraph,butwith xinradiansthefunctionhasoscillatedseveraltimes.Sothesearequitedifferent<strong>functions</strong>.Sometimes,insteadoffindingthesineofanangle,wewanttoworkbackwards. Wewanttofindananglewhosesineis,say, 3 4 . Sowewanttodefineanewfunctiontogiveustheinversesineofthenumber. Wewanttofinda<strong>functions</strong>uchthat f −1 (x) = ywhenever f(y) = x. Inourcase,wewant sin x = 3 4 ,sothatweshallwanttohave sin−1 ( 3 4 ) = x.Nowthismightseemtobeaproblematfirstbecause,ifwelookbackatourgraph,weseethattherearelotsofangleswith sin x = 3 4 .f(x)1f(x) = sin x34−360°0360° 720°x−1Wecannotdefineafunctiontotelluswhattheinversesineof 3 4 shouldbeifthereisachoiceofvaluesfor f −1 (x). Togetaroundthisproblem,weneedtorestrictthedomainofourfunctionf(x) = sin xsothatwehaveonlyapartofthegraphthatgivesusoneangleforeachsinevalue.Thishappensifwecutourdomaindownto −90 ◦ ≤ x ≤ 90 ◦ ,or −π ≤ x ≤ πifweworkinradians.c○mathcentreJune25,2009 www.mathcentre.ac.uk 4 mc-TY-trig-2009-1

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