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Probability - the Australian Mathematical Sciences Institute

Probability - the Australian Mathematical Sciences Institute

Probability - the Australian Mathematical Sciences Institute

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{36} • <strong>Probability</strong>A1HA2A3A4A5A6εA partition of <strong>the</strong> event space and <strong>the</strong>intersection of an event H with <strong>the</strong> partition.The simplest version of a partition is any event A and its complement, since A ∩ A ′ = ∅and A ∪ A ′ = E .Note <strong>the</strong> event H represented on <strong>the</strong> diagram of <strong>the</strong> event space E above. It appears from<strong>the</strong> diagram that <strong>the</strong> probability of H can be obtained by summing <strong>the</strong> probabilities of<strong>the</strong> intersection of H with each event A i in <strong>the</strong> partition. We can show this formally:H = H ∩ E= H ∩ (A 1 ∪ A 2 ∪ ··· ∪ A k )= (H ∩ A 1 ) ∪ (H ∩ A 2 ) ∪ ··· ∪ (H ∩ A k ).Since A 1 , A 2 ,..., A k are mutually exclusive, it follows that <strong>the</strong> eventsH ∩ A 1 , H ∩ A 2 , ..., H ∩ A kare also mutually exclusive. Hence, by <strong>the</strong> third axiom of probability,Pr(H) = Pr(H ∩ A 1 ) + Pr(H ∩ A 2 ) + ··· + Pr(H ∩ A k )= Pr(A 1 )Pr(H|A 1 ) + Pr(A 2 )Pr(H|A 2 ) + ··· + Pr(A k )Pr(H|A k )k∑= Pr(A i )Pr(H|A i ).i=1This result is known as <strong>the</strong> law of total probability. Note that it does not matter if <strong>the</strong>reare some events A j in <strong>the</strong> partition for which H ∩ A j = ∅. (For example, see A 1 and A 6 in<strong>the</strong> diagram above.) For <strong>the</strong>se events, Pr(H ∩ A j ) = 0.A table can provide a useful alternative way to represent <strong>the</strong> partition and <strong>the</strong> event Hshown in <strong>the</strong> diagram above. In <strong>the</strong> following table, <strong>the</strong> event A 3 is used as an example.

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