Worked solutions Chapter 3 Gravity and satellites - PEGSnet
Worked solutions Chapter 3 Gravity and satellites - PEGSnet
Worked solutions Chapter 3 Gravity and satellites - PEGSnet
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<strong>Worked</strong> <strong>solutions</strong><strong>Chapter</strong> 3 <strong>Gravity</strong> <strong>and</strong> <strong>satellites</strong>F g = mg = 55 × 9.8 = 539 N ↓∑F = F N + F gF N = ∑F – F g = 990 N ↑ – 539 N ↓ = 1529 N ↑ = 1.5 × 10 3 N up48 The apparent weight is given by the normal force of 1350 N. This is almost three times largerthan the weight force <strong>and</strong> so the skater would feel much heavier than usual.4950 a Cb One force acts on the floor <strong>and</strong> the other force acts on the ball. These forces are equal inmagnitude as described in Newton’s third law.Heinemann Physics 12(3e)Copyright © Pearson Education Australia 2008Teacher’s Resource <strong>and</strong> Assessment Disk(a division of Pearson Australia Group Pty Ltd) ISBN 978144250126316
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