3(m n)a(x1)g)h)2tx19s s s sThe opposite to is or equivalently , . All students were right.t tt t202a 2a2a2a c (2a c)2a ca) b) b b b 2d2d2d212x 4y2x y 2x 7y3x y 2x 3y 12na)b)c)d)e)f)333 ttk t3(a b) 2( cd 1) ( 2 a ) 3( m n)g)h)txy22 a)x3xx 3x1a b 1 b) 3 c) 3xd) ( a b)y yy y y yy y23 a) 4 a b) 32ac) 2 a d) 64 x e) not possible f) not possible g) 2 x h) 2 xmi) 32j) x2k) xy l) not possible m) 2 x n) 2 x86ybdo) x p) q) 1 x r)5xz 3acs) 0.06xyzt) 4x24 Yes, both are equivalent.25 (x+y)(1+a) and x+y(1+a) are not equivalent. In (x+y)(1+a) the entire expression of (x+y) is multiplied with (1+a) andin x+y(1+a) only y is multiplied with (1+a).26 a) a 2 b c c 2b a b) x x 44 xy 1c) xy4 4aa 2 2e)x y x yab b f) z c c z g) xyz yz( x)h) a 3 3 32 227m m , ,1 1m (1)are equivalent to m.28 m (n)and n m are equivalent to m n :29 a b c d and d b c a are equivalent to a c b d .30 a 1 2aa, a , , are equivalent to a .b b 2b bb31 All of the expressions are equal to32x 4x x, , and2 8 233 8a 3, 3 a 8,345x except656xare equivalent to x 23 8a2 are equivalent to 3 8a21 3ab b 3a1(3a b), ,, and (3a b)are equivalent to66 6 66m n 1 11 n m are equivalent to35m n, m n,( m n) and .3 3 33 33 336 Both John and Mary are right.37 ( )4 4x 1, x 1. Since 1 1 the expressions are not equivalent.2 238 y 53a b .6x , ( x y)2 1, when x 1, y 2 . Since 5 1 the expressions are not equivalent.n ( 1)m 11 m 1, when m 1 b) ( 1)m 1,1 m 1, when m 339 m−n+p=−2, m− (n+p)= −4,when m=2, n=5 5 ,and p=1. Since −2 −4 the expressions are not equivalent.40 a) , m 1 m 1, when m 5 d) ( 1)m 1,1 m 1, when m 7c) ( 1) 1,120Answers to <strong>Exercises</strong>
Lesson 4e) No, we cannot. Even if the expressions have the same answers in a-d, we cannot conclude that the expression willalways be equivalent. f) (−1) m =1, −1 m =−1, when m=2. Yes, we can, they are not equivalent. It is enough to findone set of values of variables for which two expressions are not equal to determine that they are not equivalent.1 coefficient, exponent or power, the base.2 a) first b) zero3 a) b b) ab c) de d) ─a e) a f) 2x y 43 a4 a)2 2 2 b) a c) d) ( 5a ) e) 3 75 base exponent coefficienta) x 4 3b) x m −16 a)3cc) x 323d) a bc2 −1e)xym 1f) x y714g)3x z37w4h) ab 51256 b)i) m+ n 2 +m j)34z c)3 a3 4 d) x5 y 2 e)34k k k k) z z zn n314z28a f)4 a a f)l) x y ( z)3z z z5( x) g)10 x2 2x y xy g)m)xx243 x3( a b) h) n) 2a 3 o) p) q)r) b x3 s) m n)m n( w 2v) m ( m p n)7 a) (−4) (−4) (−4) (−4) (−4) b) −4∙4∙4∙4∙4 c) (−m) (−m) (−m) d) −m∙ m∙ me) ( 2a )(2a)(2a)f) 2 a a ag) ( a b)(a b)h) a b b8 a) 1 b) 3 c) x d) a e) ab f) 1 g) ab 1h) 193a) x4b) ( x) , necessary7c) xd)3, necessarye)( b3a 2 ) , necessary f)3a 2bg)3a )2( 2t3 ) 4( 3 x)2( t) ( n m p)m( bc , necessary h)a ( 2b) 2x y 4, necessary10 a) 2,000,000 b) 8,000,000The answers are different, since the order of operations is different. In part b, we must first complete operations withinparentheses.11 a) To multiply exponential expressions with the same bases one needs to add the exponents.b) To divide exponential expressions with the same bases one needs to subtract their exponentsc) To raise an exponential expression to another power one needs to multiply exponents.12 a)i)23n b)169a j)14s c)12x k)6x d)1 a23 l)28b e)3x m)216x f)326a n)902m g) b h) 115s o)12 5t p)x 1218x3Answers to <strong>Exercises</strong> 121
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Math 017MaterialsWithExercises
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TABLE OF CONTENTSLesson 1Variables
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Lesson 1___________________________
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e) „minus x ‟ or „the opposit
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For example,Evaluate 5 x when x 10
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3xd) x( y)e) 2f) 2x yz w(t)Ex.4 T
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Ex.16 Let x 3. Rewrite the express
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e) x5f) x2Ex.28 Substitute“undefi
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Lesson 2___________________________
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Solution:Please, notice the use of
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g)i)4( a 2)h)8y (x)4(ab)j) ( a d)
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1 2Ex.19 If possible, evaluate when
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Lesson 3___________________________
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Commutative Propertyof Additionx y
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2 x 2 xFor example, and thus als
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Example 3.10 Determine which of the
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Exercises with Answers (For answers
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Ex.16 Write the following expressio
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s) ( 0.2xy)( 0.3z)t)4x1Ex.24 Is 1
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Lesson 4___________________________
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Numerical coefficientsNumerical Coe
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For your convenience, we will displ
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9 818081a) 9 98097 6 76134 4 4 4
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Ex.8Simplify by raising to the indi
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73a 2xxi) 2aj)2( 42a)x(3xk)4x2 ) 3
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Lesson 5___________________________
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FactorizationThe Distributive Law l
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Simplification of algebraic fractio
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Mistake 5.1When factoring 3 from 3x
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Ex.13 Factor2a) 5 a from the follow
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24x ( 5x)g)xa bi)7(a b)bc ( b e)
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Adding and subtracting like termsIf
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) This should be written as 4x 2
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Ex.4 Circle all terms that are like
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682 122k) 6 ( d a) a dl) 3a1(4a
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- Page 94 and 95: xy x 1 yFactor x .x( y 1)1yDivide
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- Page 108 and 109: Example 11.2 The expression( 22 2x
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- Page 118 and 119: APPENDIX A:Lesson 1ANSWERS TO EXERC
- Page 120 and 121: 49C 3255 2(L+W)62mc75a) a b expon
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