Practice Questions Placement Exam for Entry into Chemistry 120

Potentially Useful InformationAvogadro's number = 6.0221420×10 23h = 6.6260688×10 −34 J sc = 2.9979246×10 8 m/s1amu = 1.6605387×10 −27 kg1MeV = 1.60217646 ×10 −13 J1Å=10 −10 mcE= λν= hν2E = mch hλ = =p mvh( ∆x)( ∆p)≥4π12mv = hν−φ2−18− 2.179×10 JE n=2n∆E = q+ww=−p∆VH = E + PVq =∆ Hq = mc( ∆ T)q = C( ∆ T)K∆S⎛ ⎞= ⎜ ⎟⎝ P ⎠ocRTPKc osurr∆H= −TG = H − TSsys∆n∆G = ∆H − T∆SG = G + RT ln P∆G = ∆G + RT ln Q∆G = −RT ln K ∆H∆Sln K =− +RT RK = 273.15 + °CR = 8.314 J mol −1 K −1= 0.0821 liter atm mol −1 K −1= 1.987 cal mol −1 K −11 atm = 760 TorrPV = nRTaA +bB → cC +dDd A dCrate = − 1 [ ] 1 [ ]=a dt c dtxRate = k [ A] [ B]1 1− = kt[ A] [ A] 0ln[ A] = − kt+ln[ A] 0[ A] = - kt+[ A] 0t12 /t12 /t12 /1=kA [ ][ A]=2k000.693=kk = Ae− EaRTy