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Solutions Pamphlet

Solutions Pamphlet

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<strong>Solutions</strong> AMC 8 2002 519. (D) Numbers with exactly one zero have the form 0 or 0, where the blanksare not zeros. There are (9 · 1 · 9) + (9 · 9 · 1) = 81 + 81 = 162 such numbers.20. (D) Segments AD and BE are drawn perpendicular to Y Z. Segments AB,AC and BC divide △XY Z into four congruent triangles. Vertical line segmentsAD, XC and BE divide each of these in half. Three of the eight smalltriangles are shaded, or 3 8 of △XY Z. The shaded area is 3 8(8) = 3.XABYDCEZORSegments AB, AC and BC divide △XY Z into four congruent triangles, sothe area of △XAB is one-fourth the area of △XY Z. That makes the areaof trapezoid ABZY three-fourths the area of △XY Z. The shaded area isone-half the area of trapezoid ABZY , or three-eighths the area of △XY Z,and 3 8(8) = 3.21. (E) There are 16 possible outcomes: HHHH, HHHT , HHT H, HT HH,T HHH, HHT T , HT HT , HT T H, T HT H, T HHT , T T HH and HT T T ,T HT T , T T HT , T T T H, T T T T . The first eleven have at least as many headsas tails. The probability is 1116 .22. (C) When viewed from the top and bottom, there are 4 faces exposed; fromthe left and right sides, there are 4 faces exposed and from the front and back,there are 5 faces exposed. The total is 4 + 4 + 4 + 4 + 5 + 5 = 26 exposedfaces.ORBefore the cubes were glued together, there were 6 × 6 = 36 faces exposed.Five pairs of faces were glued together, so 5 × 2 = 10 faces were no longerexposed. This leaves 36 − 10 = 26 exposed faces.

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