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GCSE Physics for CCEA second editionii) Stage CD = area of triangle = ½ x b x h = ½ 125 x 10 = 625 m(3 marks)total distancee) averagespeed =total time250 500 625= 6.11 m/s (3 marks)225f) work done = force x distance = 5000N x 500m = 2500 000J (3 marks)4. a) i) speed = gradient = 14m ÷ 7s = 2m/s (2 marks)ii)(2 marks)b) i) potential energy = mass x g x height320 000J = 80 kg x 10 m/s 2 x heightheight = 320 000 ÷ 800 = 400m(3 marks)ii) kinetic energy = ½ x m x v 2= ½ x 80 x 14 2= 7840J (3 marks)6
GCSE Physics for CCEA second editionIn-text questionsChapter 2 Forces1. a) No acceleration means balanced forces, so there must be a backwards force of 40N acting onbicycle and rider; friction and air resistance.b) RF = 70 – 40 = 30N, m = 90kg, a = ?RF = m x a30 = 90 x aa = 30 ÷ 90 = 0.33m/s 22. m = 1200 kg, a = 2 m/s 2 , RF = (3000 – frictional force)RF = m x a3000 – frictional force = 1200 x 23000 – frictional force = 24003000 – 2400 = frictional force600 = frictional forceor frictional force = 600N3. a) Forwards.b) Consider horizontal forces only. RF = (2000 – 400) = 1600N, m = 800kg, a = ?RF = m x a1600 = 800 x aa = 1600 ÷ 800 = 2m/s 24. a) weight = mass x acceleration due to gravity= 2000 kg x 10 m/s 2= 20000Nb) Consider vertical forces. RF = (25000 – 20000) = 5000N, m = 2000kg, a = ?RF = m x a5000 = 2000 x aa = 5000 ÷ 2000 = 2.5m/s 25. 300N forward thrust. Frictional force due to water must also be 300N backwards, if it travels atconstant speed. RF = (? - 300), m = 500kg, a = 2 m/s 2RF = m x a(? -300) = 500 x 2(? -300) = 1000? = 1000 + 300= 1300N6. RF = (? - 400) N, m = 1200kg, a = 3m/s 2RF = m x a(? -400) = 1200 x 3(? -400) = 3600? = 3600 + 400= 4000N7. a) u = 24m/s, v = 0m/s (brings to rest), t = 8s, a = ?7
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