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Simplified models/procedures forest
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Simplifiedmodels/proceduresfor esti
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iiiTABLE OF CONTENTSLIST OF TABLES
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vLIST OF TABLESTable 1 Mechanical p
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viiLIST OF FIGURESFigure 1 (a) Rein
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xFigure 68 Average stress-strain re
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xivν xywxyyA gA hA vCC sD= Shear s
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11. INTRODUCTIONA number of importa
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3On the basis of these results, it
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53. NUMERICAL MODEL3.1 GENERALITIES
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7⎛ 8 ⎞ ⎛ s ⎞ ⎛ s ⎞α =
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9less clear if the numerical model
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11longitudinal reinforcement ratio
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13where A c is the concrete gross s
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15where B and H are the section wid
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17whereξW2πE=dd(5.10)χ yLEd = μ
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20Another series of tests carried o
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22Rectangular case, section 2-2:F =
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24concrete struts can form with the
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269.1 PRIESTLEY ET AL. [1994]Accord
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28is given by Equation (7.1), the p
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30edges remain straight and paralle
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32of principal stresses in the conc
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34vci max0.18 ⋅ fc′=0.3 + 24
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36F = F + C − C(9.40)k k−1 k1 k
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38that there is a fundamental diffe
- Page 59 and 60: 40where α i defines the reinforcem
- Page 61 and 62: 42where⎡N( Ec3 −Ec2)⋅Δε⎤f
- Page 63 and 64: 44where1βt= (13.37)1 + 1.15 ⋅rec
- Page 65 and 66: 46• Acknowledging that hollow sec
- Page 67 and 68: 48Menegotto, M., Pinto, P.E. [1973]
- Page 69 and 70: 50CSA Committee A23.3 [1994] Design
- Page 71 and 72: 52Wong, Y.L., Paulay, T., Priestley
- Page 73 and 74: 54Table 4 Values of the parameters
- Page 75 and 76: 56Table 13 Values of factor α s de
- Page 77 and 78: 58PART BTable 23 Values of θ and
- Page 79 and 80: 60100800Displacement [mm]500-504000
- Page 81 and 82: 6260004000Moment [kN*m]20000-2000-4
- Page 83 and 84: 64NumericalExperimentalSlice #3Figu
- Page 85 and 86: 66NumericalExperimentalSlice #4Figu
- Page 87 and 88: 680.04 (3)0.03 (3)(3)1.20.02 (3)0.4
- Page 89 and 90: 702010 -2181614121, 2, 31, 2, 32 3
- Page 91 and 92: 72μ2018161412108642χ y* H10 -28.0
- Page 93 and 94: 7420181614121 to 51 to 510 -28.0x10
- Page 95 and 96: 762010 -2μ18161412108642031212 3 1
- Page 97 and 98: 78μ2018161412108642χ y* H10 -28.0
- Page 99 and 100: 80μ201816141 to 53214513to52χ y*
- Page 101 and 102: 82μ201816141210864203213213213211
- Page 103 and 104: 840.400.35ρ = 0.0050.400.35ρ = 0.
- Page 105 and 106: 86Compression chordPART B2PTransver
- Page 107 and 108: 88Figure 64 Contribution of axial f
- Page 109: 90Figure 70 (a) Calculated average
- Page 113: The mission of the JRC is to provid