Chapter 6.2 Notes

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• Since humans have 23 pairs of homologouschromosomes…each pair has ____ 2 ways it may facewhile lining up• Mathematically, the total number of possible gametesformed is…2 n or 2 23 = 8,388,608 gametes<strong>Chapter</strong> menuResourcesCopyright © by Holt, Rinehart and Winston. All rights reserved.
Random fertilizationfuse• Each of the possible gametes (2 23 ) must _______ withanother one of the possible gametes (2 23 ) duringfertilization– Mathematically, the total number of possible zygotesis…2 23 x 2 23 = 70,368,744,000,000 zygotes• So many different ________________ with great_________________ may resultvariationoffspring<strong>Chapter</strong> menuResourcesCopyright © by Holt, Rinehart and Winston. All rights reserved.
Page 1 and 2: Chapter 6.2Meiosis and Sexual Repro
Page 3 and 4: • Meiosis• Crossing over• Ind
Page 5 and 6: • What are the two types of human
Page 7 and 8: • Meiosis I includes….- Prophas
Page 9 and 10: Prophase I• This stage differs fr
Page 11 and 12: • Since they are not identical,th
Page 13 and 14: • During crossing over, areas on
Page 15 and 16: Metaphase I• The __________ pairs
Page 17 and 18: Telophase I and CytokinesisProphase
Page 19: VERY IMPORTANT!!!!!!!!• These two
Page 22 and 23: Anaphase II• Sister _____________
Page 24 and 25: Meiosis and Genetic Variation• Me
Page 26 and 27: • In ____________________, Metaph
Page 30 and 31: Crossing over• Since homologous c
Page 32 and 33: Gamete Formation in Males and Femal
Page 34 and 35: • These haploidcells must________
Page 36 and 37: • In oogenesis, thecytoplasm does
Page 38 and 39: Objective 2• Relate crossing-over

Chapter 6.2 Notes

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