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Honors Geometry Unit #2 Review Topics: • Points ... - Nichols School

Honors Geometry Unit #2 Review Topics: • Points ... - Nichols School

Honors Geometry Unit #2 Review Topics: • Points ... - Nichols School

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6. Draw a diagram to illustrate the problem, then give an answer: ABC is trisected by BD andBE . DBE is bisected by BX . If mABC = 81°, what is mDBX?7. Two complementary angles are in a ratio of 7:8. Find the measure of the smaller angle.8. One of two supplementary angles is 30 more than 5 times the other. What is the measure of thelarger angle?9. If M is the midpoint of AB ,AM2 x 1 and3AB x 585, find BM.10. Find the measure of each numbered angle in the diagram below.654333°1 211. In the diagram below, m15x2 y, m26x10y 7, and m380 7y. Are the linesperpendicular? Show all of your work and give an explanation of your answer.123***Note: In addition to problems similar to the ones above there will be some True/False questions onyour test.<strong>Unit</strong> <strong>#2</strong> <strong>Review</strong> Key:1. a. ex: H,I,J b. ex: A,E,F,D c. ex: H,I,L d. ex: H,I,L,E e. D f. HJ g. G h. AD i. IL52. b. 6 2 c. (4, ) d. 1 and 2/7; neither23. -5/2 < x < 25/24. -6 and 45. Since x is 7, mM = 84°, so M is not a right angle.6. 13.5°7. 84°8. 155°9. 710. m1 = m2 = 90°; m3 = 147°; m4 = 33°; m5 = m6 = 147°11. x = 15 and y = -1; m1 = 73° so the lines are not perpendicular.

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