3B Type-substitutions 353B1 Notation As defined in 3A1 a substitution is just a finite sequence of instructions§ _ [at /al, ... , 6n/an] saying "simultaneously substitute of for at, ... , a, for an". Thefollowing extra notation will be useful.'The case n = 0 will be allowed and called the empty substitution, e. Soe(T) _ T.If n = 1, s will be called a single substitution.Each part-expression a1/al of s will be called a component of s, and called trivialif o, = ai.If all trivial components are deleted from s the resulting substitution will be calledthe nontrivial kernel of s.The set {a,,...,an} will be called Dom(s) or the variable-domain of s.And Vars(ot,...,an) will be called Range(s) or the variable-range of s.3B2 Definition Substitutions s and t are extensionally equivalent (s =ext t) if s(T)I(T) for all T.3B2.1 Lemma (i) b Dom(s) s(b) _ b.(ii) § =ext tiff s and t have the same non-trivial kernel.3B3 Definition (Restriction, s r V) If s - [at/at,...,Un/an] and V is a given setof variables, the restriction s r V of s to V is the substitution consisting of thecomponents of/ai of s such that ai E V.3B3.1 Lemma (s [ Vars(T))(T) = s(T).3B4 Definition (Union) If s _ [at/at,...,vn/an] and t _ [T,/bt,...,Tp/bp] and eithera1.... , an, bt, ... , by are all distinct or ai = b1 (Ti = r1, define(with repetitions omitted).sUt = [al/al,...,Qnlan,Tllbl,...,Tplbp]3B4.1 Lemma (i) Dom(s U t) = Dom(s) U Dom(t).(ii) If § =ext s' and I =ext t' and s U t is defined, then so is s' U C and§ U t =ext § U t'.The next definition will be the composition of two substitutions s and t, asimultaneous substitution that will have the same effect as applying t and s insuccession. To motivate it, consider the case§ - [(c-+d)/a, (b->a)/b], I - [(b->a)/b]and let T = a-+b. The result of applying first t then s is easily seen to bes(t(T)) _ (c->d)-(b--*a)-+(c->d);There seems to be no standard substitution notation in the literature.
36 3 The principal-type algorithmthe problem is to find a simultaneous substitution having the same effect. A naiveattempt to use s U t would fail, because(s U t)(T) = s(T) _ (c--+d)-+b-+a.But there does exist a suitable substitution, namely[(c-'d)l a, (s(b-*a))l b]This special case is generalized as follows.3B5 Definition (Composition) If s and t are any substitutions, saydefines =t = [Tt/b1,...,Tp/bp],s o t = [ai, /ai...... air, l ai,,, s(T1)/b1,... , s(T4)/bp]where {ai,,...,ai,,} = Dom(s) -Dom(t) and 0< h< n.3B5.1 Lemma (i) Dom(s o t) = Dom(s) U Dom(t).(ii) (s o t)(T) = S(t(T)).(iii) r o (s o t) =ext(r o s) o t.(iv) s =ext s', t =ext t' § o t =ext s' o(v) By (ii), an instance of an instance of T is an instance of T.3B5.2 Exercise* (i) Write out s o t in the special case that s - [alb] and I = [b/a],and verify that (s o t)(T) = s(t(T)) in the case T - a-*b.(ii) Show that the action of any s on a given type T can be expressed as acomposition sl o ... o sk of single substitutions, in the sense that(sl o ... o §k)(T) = §(T)The next lemma will play an important role in the correctness proof of the PTalgorithm: it says that if a composition sot is "extended" to r U (sot), the extendedsubstitution can also be expressed as a composition with t (under certain conditionson r to prevent clashes).3B6 Composition-extension Lemma Let r, s, t be substitutions such that(i) Dom(r) n (Dom(s) U Dom(t)) = t0,(ii) Dom(r) n Range(t) = 0.Then r U (s o t) and (r U s) o t are both defined andrU(sot) - (rUs)otProof Suppose r, s, t are, respectively,[p1/al,.. , Pr/ar], [al /bl, , as/bs],with r, s, t >_ 0, and suppose(1)VDom(s)-Dom(1)={bi...... bi,,}[T1/C1,...,Tt/ct](h >_ 0).
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6C Some weaker logics 85for some cl
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6C Some weaker logics 87logic in 6A
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6D Axiom-based versions 89Deduction
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7C The converse PT proof 101Conside
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7D Condensed detachment 107Proof By
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8A Inhabitants 1118A7.1 Example Let
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8A Inhabitants113Fig. 8A12a.8A11.2
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8B Examples of the search strategy
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8C The search algorithm 119Long(s)
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8C The search algorithm 121Note. Th
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8E The structure of a nf-scheme131T
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8F Stretching, shrinking and comple
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8F Stretching, shrinking and comple
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8F Stretching, shrinking and comple
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8F Stretching, shrinking and comple
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9A The structure of a term 1419A2 D
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9B Residuals 145Proof-note Two case
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9B Residuals 1479134.1 Lemma Every
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9C The structure of a TAR-deduction
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9D The structure of a type 151below
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9E The condensed structure of a typ
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9F Imitating combinatory logic in A
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162 Answers to starred exerciseswit
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BibliographyReferences to unpublish
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Bibliography 171DOSEN, K. [1992a] M
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Bibliography 173KALMAN, J. A. [1983
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Bibliography 175SCEDROV, A. [1990]
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Table of principal typesThis table
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IndexA-logics (see axiom-based logi
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Index 181D-incompleteness of BCI, B
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Index183PT algorithm, converse (see
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Index185#-contraction 4of typed ter