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C4 June 2008 mark scheme.pdf

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EDEXCEL CORE MATHEMATICS <strong>C4</strong> (6666) – JUNE <strong>2008</strong>PROVISIONAL MARK SCHEMEQuestionNumber6. (a) Lines meet where:Scheme9 2 3 30 1 1 110 1 17 5MarksAny two ofi : 9 2 3 3 (1)j: 1 (2)k : 10 17 5 (3)M1(1) – 2(2) gives: 9 1 5 2 M1(2) gives: 1 2 3 A19 2 3 3r 0 3 1 or r 1 2 1M110 1 17 5Intersect at3r 3 or r 3i 3j 7k A17Either check k:3 : LHS 10 10 3 72 : RHS 17 5 17 10 7B1 (6)(b) d12i j k , d23i j 5k2As d 1d 1 1 (2 3) (1 1) ( 1 5) 02 31 5M1 A1 (2)Then l 1 is perpendicular to l 2 .(c) Equating i ; 9 2 5 79 2 5r 0 7 1 7 ( OA.Hence the point A lies on l 1 .) B1 (1)10 1 3(d) Let OX 3i 3j 7k be point of intersection3 5 8AX OX OA 3 7 4M1 ft7 3 4OB OA AB OA 2AX4

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