Webreview cp physics ch 3 practice test (holt)
Webreview cp physics ch 3 practice test (holt) - Planet Holloway
Webreview cp physics ch 3 practice test (holt) - Planet Holloway
You also want an ePaper? Increase the reach of your titles
YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.
ID: A<br />
20. 45.6 m at 80.5° south of east<br />
Given<br />
d 1<br />
= 45.0 m south<br />
d 2<br />
= 7.50 m east<br />
Solution<br />
Δx = d 2<br />
= 7.50 m<br />
Δy = d 1<br />
= 45.0 m<br />
d 2 = Δx 2 + Δy 2<br />
d = Δx 2 + Δy 2 = (7.50 m) 2 + (45.0 m) 2 = 45.6 m<br />
Ê Δy ˆ Ê<br />
θ = tan −1<br />
−1<br />
45.0 m ˆ<br />
= tan<br />
Ë<br />
Á Δx ¯<br />
˜<br />
Ë<br />
Á 7.50 m ¯<br />
˜ = 80.5°<br />
d = 45.6 m at 80.5°south of east<br />
21. 4.9 m<br />
Given<br />
d 1<br />
= 3.2 m along +y-axis<br />
d 2<br />
= 4.6 m at 195° counterclockwise from +x-axis<br />
d 1<br />
= 3.2 m θ 1<br />
= 0.0°<br />
d 2<br />
= 4.6 m θ 2<br />
= 195°<br />
Solution<br />
Δx 1<br />
= 0.0 m<br />
Δy 1<br />
= 3.2 m<br />
Δx 2<br />
= d 2<br />
cosθ 2<br />
= (4.6 m)(cos195°) = − 4.4 m<br />
Δy 2<br />
= d 2<br />
sinθ 2<br />
= (4.6 m)(sin195°) = −1.2 m<br />
Δx tot<br />
= Δx 1<br />
+ Δx 2<br />
= (0 m) + ( − 4.4 m) = − 4.4 m<br />
Δy tot<br />
= Δy 1<br />
+ Δy 2<br />
= (3.2 m) + (−1.2 m) = 2.0 m<br />
d 2 = (Δx tot<br />
) 2 + (Δy tot<br />
) 2<br />
d = (Δx tot<br />
) 2 + (Δy tot<br />
) 2 = (−4.4 m) 2 + (2.0 m) 2 = 4.9 m<br />
3
Change language