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100-105 dumps

Get high success rate in 100-105 Certification Exam with our exam PDF questions answers prepared by the authorized persons of Information Technology industry. For more info please visit here: https://www.certswarrior.com/exam/100-105/

Get high success rate in 100-105 Certification Exam with our exam PDF questions answers prepared by the authorized persons of Information Technology industry. For more info please visit here: https://www.certswarrior.com/exam/100-105/

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A. Vacant switch ports must be shut down.<br />

B. Empty ports must be enabled in VLAN 1.<br />

C. VLAN 1 must be configured as the native VLAN.<br />

D. Err-disabled ports must be configured to automatically re-enable.<br />

Answer: A<br />

Question: 10<br />

Which statement describes the effect of the overload keyword in the ip nat inside source list 90<br />

interface ethernet 0/0 overload command?<br />

A. Addresses that match address list inside are translated to the IP address of the Ethernet 0/0 interface.<br />

B. Hosts that match access inside are translated to an address m the Ethernet 0/0 network.<br />

C. Hosts on the Ethernet 0/0 LAN are translated to the address pool in access list 90.<br />

D. Addresses that match access list 90 are translated through PAT to the IP address of the Ethernet 0/0<br />

interface<br />

Explanation<br />

The command “ip nat inside source list 90 interface ethernet0/0 overload” means:<br />

+ “ip nat”: use NAT<br />

+ “inside”: NAT from inside to outside<br />

+ “source list 90”: the source addresses can be found in access list 90<br />

+ “Interface Ethernet 1”: NAT out of this interface<br />

+ “overload”: use NAT overload (PAT)<br />

Question: 11<br />

Answer: D<br />

Which technique can you use to route IPv6 traffic over an IPv4 infrastructure?<br />

A. NAT<br />

B. 6to4 tunneling<br />

C. L2TPv3<br />

D. dual-stack<br />

Question: 12<br />

Answer: B<br />

Which NAT command can be applied to an interface?<br />

Visit us athttps://www.certswarrior.com/exam/<strong>100</strong>-<strong>105</strong>/

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