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Example 2(Cont.) The ultimate strength for steel is 4089 x 10 8 Pa. . What is the maxi- mum weight that can be supported without breaking the wire? Recall: A = 3.14 x 10 -6 m 2 L A A F Stress F A 8 4.89 x 10 Pa L F = (4.89 x 10 8 Pa) A F = (4.89 x 10 8 Pa)(3.14 x 10 -6 m 2 ) F = 1536 N
The Modulus of Elasticity Provided that the elastic limit is not exceeded, an elastic deformation (strain) is directly proportional to the magnitude of the applied force per unit area (stress). Modulus of Elasticity stress strain
Page 1 and 2: Chapter 13 - Elasticity A PowerPoin
Page 3 and 4: Objectives: After completion of thi
Page 5 and 6: Elastic Properties of Matter An ine
Page 7 and 8: An Elastic Spring A spring is an ex
Page 9 and 10: Stress and Strain Stress refers to
Page 11 and 12: Summary of Definitions Stress is th
Page 13 and 14: Example 1. A steel wire 10 m long a
Page 15 and 16: The Elastic Limit The elastic limit
Page 17: Example 2. The elastic limit for st
Page 21 and 22: Young’s s Modulus For materials w
Page 23 and 24: Example 4: (Continued) Y = 8.96 x 1
Page 25 and 26: Calculating Shear Modulus F l d A S
Page 27 and 28: Volume Elasticity Not all deformati
Page 29 and 30: Example 7. A hydrostatic press cont
Page 31 and 32: Summary Types of Stress A tensile s
Page 33 and 34: Longitudinal Stress and Strain L L
Page 35 and 36: Young’s s Modulus For materials w
Page 37 and 38: The Bulk Modulus Volume stress F A

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