tutorial curve

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One circular curve of radius 250 meter will build up for connected two straights road. The chainage of intersection point, I being 2942 meter and the deflection angle being 60º 00’ 00”. The curve will be mark at every offset of 20 meter. Calculate the setting out data required to peg the curve with offset method from tangent line. Radius, R 250m Deflection angle , θ 60 0 T1 I θ = 60º 00’ 00”. T2 Offset Chainage intersection point, I 20m 2942 m R = 250 m
Tangent length = R tan θ/2 = 250 tan 60°/2 = 144.34m Chainage T 1 Arc length PROCEDU RE = chainage I – tangent length = 2942 - 144.34 = 2797.66m = 2π x R x θ 360 = 2π x 250 x 60 o = 261.8m 360 Chainage T 2 = chainage T 1 + arc length = 2797.66 + 261.8 = 3059.46m Ofset,Y R R 2 Y 2 R 2 -Y 2 √(R 2 -Y 2) X= R-√(R 2 - X = R − R 2 − Y Y 2) 2 0 250 62500 0 62500 250.000 0.000 20 250 62500 400 62100 249.199 0.801 40 250 62500 1600 60900 246.779 3.221 60 250 62500 3600 58900 242.693 7.307 80 250 62500 6400 56100 236.854 13.146 100 250 62500 10000 52500 229.129 20.871 120 250 62500 14400 48100 219.317 30.683 140 250 62500 19600 42900 207.123 42.877 144.338 250 62500 20833.333 41666.667 204.124 45.876
Page 1: Circular curves
Page 5 and 6: The centre-line of two straights is
Page 7 and 8: Radius, R 12m Deflection angle , θ
Page 9 and 10: Long chord length = 16.971 w/2 = 8.
Page 11 and 12: Radius, R Deflection Given angle ,
Page 13 and 14: Radius, R 24.7m Deflection angle ,
Page 15 and 16: I Scale 1m :1cm 1:100 T1 T2
Page 17 and 18: PROCEDUR Tangent length = R tan θ/

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