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A PRIMER OF ANALYTIC NUMBER THEORY: From Pythagoras to ...

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Theorem. The Prime Number Theorem is true:<br />

�(x) ∼ Li(x) ∼ x<br />

log(x) .<br />

10.4 Riemann’s Formula 249<br />

We won’t give the full proof here; you can find it in any other book on<br />

analytic number theory. But here are some of the ideas. We saw in the previous<br />

section that Li(x) ∼ x/ log(x). And (10.10) shows that that �(x) ∼ �(x).<br />

The main idea of the theorem is that the first term written in Riemann’s<br />

explicit formula for �(x), the Li(x) term, is actually the most significant. It<br />

dominates all the others. We already mentioned the fact that this term comes<br />

from the pole of �(s) ats = 1; that is, the Harmonic series diverges. In fact,<br />

it is known that the Prime Number Theorem is equivalent <strong>to</strong> the following<br />

theorem, which is an improvement on (10.2).<br />

Theorem. The nontrivial zeros � of �(s) satisfy<br />

0 < Re(�) < 1. (10.15)<br />

Proof. This deep result begins with the trivial trig identity that for any<br />

angle �,<br />

3 + 4 cos(�) + cos(2�) = 2(1 + cos(�)) 2 ≥ 0.<br />

We will make use of this in the series expansion for Re(log(�(s))):<br />

� �<br />

�<br />

Re log (1 − p −s ) −1<br />

�� �<br />

� ∞� 1<br />

= Re<br />

k p−ks<br />

�<br />

p<br />

= �<br />

p<br />

p<br />

∞�<br />

k=1<br />

k=1<br />

1<br />

k p−k� cos(kt log(p)).<br />

We apply this <strong>to</strong> �(1 + �), <strong>to</strong> �(1 + � + it), and <strong>to</strong> �(1 + � + 2it) and take the<br />

following clever linear combination:<br />

3Re(log(�(1 + �))) + 4Re(log(�(1 + � + it))) + Re(log(�(1 + � + 2it)))<br />

= � ∞� 1<br />

k p−k(1+�) (3 + 4 cos(kt log(p)) + cos(k2t log(p))) .<br />

p<br />

k=1<br />

According <strong>to</strong> the trig identity, this mess is ≥ 0. But the facts about logarithms<br />

in Interlude 3 imply that the left side is actually<br />

3 log(|�(1 + �)|) + 4 log(|�(1 + � + it)|) + log(|�(1 + � + 2it)|).

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