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A NOTE ON CALCULATOR USE<br />

Many of the problems in this series demand the use of a number of consecutive calculations, often adding, subtracting,<br />

multiplying or dividing the same amount in order to complete entries in a table or see a pattern. This demands (or<br />

will build) a certain amount of sophisticated use of the memory and constant functions of a simple calculator.<br />

1. To add a number such as 9 repeatedly, it is sufficient<br />

on most calculators to enter an initial number (e.g.<br />

30) then press + 9 = = = = to add 9 over and over.<br />

• 30, 39, 48, 57, 66, …<br />

• To add 9 to a range of numbers, enter the first number<br />

(e.g. 30) then press + 9 = 30 + 9 = 39, 7 = gives 16, 3 =<br />

gives 12, 21 = gives 30, …<br />

• These are the answers when 9 is added to each<br />

number.<br />

2. To subtract a number such as 5 repeatedly, it is<br />

sufficient on most calculators to enter an initial<br />

number (e.g. 92) then press – 5 = = = = to subtract 5<br />

over and over.<br />

• 92, 87, 82, 77, 62, …<br />

• To subtract 5 from a range of numbers, enter the first<br />

number (e.g. 92) then press – 5 = 95 – 5 = 37, 68 =<br />

gives 63, 43 = gives 38, 72 = gives 67, …<br />

• These are the answers when 5 is subtracted from each<br />

number.<br />

3. To multiply a number such as 10 repeatedly, most<br />

calculators now reverse the order in which the<br />

numbers are entered. Enter 10 x, then press an initial<br />

number (e.g. 15) = = = = to multiply by 10 over and<br />

over.<br />

• 10, 150, 1500, 15 000, 150 000, …<br />

• These are the answers when the given number is<br />

divided by 8.<br />

• This also allows squaring of numbers: 4 x = gives 16 or<br />

42.<br />

• Continuing to press = gives more powers:<br />

• 4 x = = gives 43 or 64, 4 x = = = gives 44; 4 x = = = =<br />

gives 45 and so on.<br />

• To multiply a range of<br />

numbers by 10, enter 10 x<br />

then the first number (e.g. 90)<br />

and =<br />

• 10 x 90 = 900, 45 = gives 450,<br />

21 = gives 210, 162 = gives<br />

1620, …<br />

• These are the answers when<br />

each number is multiplied by<br />

10.<br />

CALCULATOR BSCX56<br />

AC %<br />

900<br />

ON<br />

OFF<br />

MRC M– M+ CE<br />

7 8 9 ÷<br />

4 5 6 x<br />

1 2 3 –<br />

0 . = +<br />

4. To divide by a number such as 8 repeatedly, enter a<br />

number (e.g. 128).<br />

• Then press ÷ 4 = = = = to divide each result by 4.<br />

• 32, 16, 8 , 2, 0.5, …<br />

• These are the answers when the given number is<br />

divided by 8.<br />

• To divide a range of numbers by 8, enter the first<br />

number (e.g. 90) and ÷ 4 = 128 ÷ 4 = 32, 64 = gives 4,<br />

32 = gives 8, 12 = gives 1.5, …<br />

• These are the answers when each number is divided<br />

by 8.<br />

5. Using the memory keys M+, M– and MR will also<br />

simplify calculations. A result can be calculated and<br />

added to memory (M+). Then a second result can be<br />

calculated and added to (M+) or subtracted from (M–)<br />

the result in the memory. Pressing MR will display<br />

the result. Often this will need to be performed for<br />

several examples as they are entered onto a table or<br />

patterns are explored directly. Clearing the memory<br />

after each completed calculation is essential!<br />

A number of calculations may also need to be<br />

made before addition, subtraction, multiplication<br />

or division with a given number. That number can<br />

be placed in memory and used each time without<br />

needing to be re-keyed.<br />

6. The % key can be used to find percentage increases<br />

and decreases directly.<br />

• To increase or decrease a number by a certain per cent<br />

(e.g. 20%), simply key the number press = 20% or –<br />

20% to get the answer:<br />

• 80 + 20% gives 96 (not 100) – 20% of 80 is 16, 80 + 16<br />

is 96.<br />

• 90 – 20% gives 72 (not 70) – 20% of 90 is 18, 90 – 18<br />

is 72.<br />

7. While the square root key can be used directly,<br />

finding other roots is best done by a ‘try and<br />

adjust’ approach using the multiplication constant<br />

described above (in point 3).<br />

xx<br />

<strong>Problem</strong>-<strong>solving</strong> in mathematics www.ricpublications.com.au R.I.C. Publications ®

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