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⎛ m<br />

I = ⎜1kg<br />

⋅10<br />

⎝ s<br />

m<br />

m<br />

m ⎞<br />

2<br />

( 0,4m) 2<br />

− 0,1 ⋅1kg<br />

⋅10<br />

−1kg<br />

⋅ 4 −1kg<br />

⋅ 4<br />

= 0, 04<br />

2 2<br />

2<br />

2<br />

⎟<br />

m<br />

s s s ⎠ 4 2<br />

s<br />

kg ⋅ m<br />

Como el momen<strong>to</strong> de inercia de un cilindro, respec<strong>to</strong> a su eje de revolución es<br />

I<br />

1<br />

2<br />

0,04 kg ⋅ m<br />

= .<br />

(0,4m)<br />

2<br />

2<br />

= m<br />

polea<br />

R se deduce que la masa de la polea es m polea<br />

2 = 50 kg<br />

2<br />

El radio de giro es<br />

K =<br />

I<br />

m<br />

polea<br />

= 0,028 m

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