30.07.2016 Views

PRACTICA 2

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0.5<br />

1000 mg<br />

1 g.<br />

= 500 mg.<br />

- Cantidad de gramos de polvo a trabajar presentes en 100 mg. de P.A.<br />

500 mg. 100 mg. P.A.<br />

X 200 mg. P.A.<br />

X= 1000mg.<br />

- Convertido a g. equivale a:<br />

1 g<br />

1000 mg. = 1 g<br />

1000 mg.<br />

- Consumo teórico<br />

1 ml sol. NaOH 25,43 mg P.A.<br />

X 200 mg P.A.<br />

X= 7-86 ml NaOH 0.1 N<br />

- Porcentaje teórico<br />

1 ml sol. NaOH 25,43 mg P.A. 200 mg. P.A. 100%<br />

7.86 ml NaOH X 200 mg. P.A. X<br />

X= 200mg. P.A. X= 100 %<br />

- Consumo real<br />

CR= (Consumo practico x K)<br />

CR= (10.8 ml x 1.0053)<br />

CR= 10.85 ml<br />

- Porcentaje real<br />

1 ml sol. NaOH 25,43 mg P.A. 200 mg 100%<br />

10.85 ml X 276.09 mg P.A. X<br />

X= 276.09 mg P.A. X= 138.04 % P.A.<br />

LA CALIDAD ESTA EN TI, NO DEJES QUE OTROS SUFRAN LAS CONSECUENCIAS 10

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