differentiation
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316 DIFFERENTIAL CALCULUS<br />
[<br />
(a) x = 4(θ − sin θ),<br />
hence dx<br />
(a) − 1 ]<br />
1<br />
cot θ (b) −<br />
= 4 − 4 cos θ = 4(1 − cos θ)<br />
4 16 cosec3 θ<br />
dθ dy<br />
y = 4(1 − cos θ), hence dy<br />
4. Evaluate at θ = π radians for the<br />
dθ = 4 sin θ<br />
dx 6<br />
hyperbola whose parametric equations are<br />
x = 3 sec θ, y = 6 tan θ. [4]<br />
From equation (1),<br />
dy<br />
5. The parametric equations for a rectangular<br />
dy<br />
dx = dθ 4 sin θ<br />
=<br />
dx 4(1 − cos θ) = sin θ<br />
hyperbola are x = 2t, y = 2 dy<br />
. Evaluate<br />
t dx<br />
(1 − cos θ) when t = 0.40<br />
[−6.25]<br />
dθ<br />
The equation of a tangent drawn to a curve at<br />
(b) From equation (2),<br />
point (x<br />
( ) ( )<br />
1 , y 1 ) is given by:<br />
d dy d sin θ<br />
d 2 y<br />
dx 2 = dθ dx dθ 1 − cos θ<br />
y − y 1 = dy 1<br />
(x − x 1 )<br />
=<br />
dx 1<br />
dx 4(1 − cos θ)<br />
Use this in Problems 6 and 7.<br />
dθ<br />
6. Determine the equation of the tangent drawn<br />
(1 − cos θ)(cos θ) − (sin θ)(sin θ)<br />
(1 − cos θ)<br />
=<br />
2<br />
to the ellipse x = 3 cos θ, y = 2 sin θ at θ = π 6 .<br />
[y =−1.155x + 4]<br />
4(1 − cos θ)<br />
= cos θ − cos2 θ − sin 2 θ<br />
7. Determine the equation of the tangent drawn<br />
4(1 − cos θ) 3<br />
to the rectangular hyperbola x = 5t, y = 5<br />
= cos θ − ( cos 2 θ + sin 2 θ )<br />
t at<br />
t = 2. [<br />
4(1 − cos θ) 3<br />
y =− 1 ]<br />
4 x + 5<br />
= cos θ − 1<br />
4(1 − cos θ) 3<br />
−(1 − cos θ)<br />
=<br />
4(1 − cos θ) 3 = −1 29.4 Further worked problems on<br />
4(1 − cos θ) 2<br />
<strong>differentiation</strong> of parametric<br />
equations<br />
Now try the following exercise.<br />
Problem 5. The equation of the normal drawn<br />
Exercise 128 Further problems on <strong>differentiation</strong><br />
of parametric equations<br />
to a curve at point (x 1 , y 1 ) is given by:<br />
1. Given x = 3t − 1 and y = t(t − 1), [ determine ]<br />
y − y 1 =− 1 (x − x<br />
dy<br />
1<br />
dy 1 )<br />
1<br />
dx in terms of t. 3 (2t − 1) dx 1<br />
2. A parabola has parametric equations:<br />
Determine the equation of the normal drawn to<br />
x = t 2 , y = 2t. Evaluate dy<br />
dx when t = 0.5 the astroid x = 2 cos 3 θ, y = 2 sin 3 θ at the point<br />
θ = π<br />
[2] 4<br />
3. The parametric equations for an ellipse<br />
are x = 4 cos θ, y = sin θ. Determine (a) dy x = 2 cos 3 θ, hence dx<br />
dx<br />
dθ =−6 cos2 θ sin θ<br />
(b) d2 y<br />
dx 2 y = 2 sin 3 θ, hence dy<br />
dθ = 6 sin2 θ cos θ