03.05.2013 Views

Concurrency en race condities

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Maak e<strong>en</strong> tell<strong>en</strong>de semafoor met binaire<br />

(oplossing is niet goed - waarom?)<br />

class countingSemaphore<br />

{<br />

procedure Wait();<br />

begin<br />

mutex.WaitB();<br />

s = s - 1;<br />

if s < 0 th<strong>en</strong> begin<br />

mutex.SignalB();<br />

delay.WaitB()<br />

<strong>en</strong>d<br />

else<br />

mutex.SignalB()<br />

<strong>en</strong>d;<br />

procedure Signal();<br />

begin<br />

mutex.WaitB();<br />

s = s + 1;<br />

if s

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